Answer:
Mass of Fe = 32.55 g
Explanation:
The molar mass of a single Fe atom is 55.845 g/mol
This means that
1 mole of Fe equals = 55.845 g ..............(1)
According to the mole concept,[ [TAG_24]]
1 mole of Fe contains = 
atom..........(2)
If we substitute 1 mole in equation (2) with 55.845 g, it becomes:
55.845 g of Fe contains = atoms
Reversing the equation yields
atoms of Fe correspond to 55.845 g
1 atom of Fe corresponds to 
g
one atom corresponds to
On computation,
one atom corresponds to 32.55 g of Fe
Mass of Fe = 32.55 g
3,048 minutes. Explanation: 762 divided by 5, then multiply that number by 20.
The percentage of calcium carbonate that reacted is 2.5%. The reaction in question allows us to determine the equilibrium Kp: Kp = the partial pressure of carbon dioxide, since the other components are solids. We'll apply the ICE table to the provided equilibrium. At the start, we have 0.2 for calcium carbonate with no initial moles of other substances. As the reaction progresses, we set the changes to be -x for calcium carbonate, +x for carbon dioxide, and +x for the other product, leading us to an equilibrium of 0.2-x for calcium carbonate while both other products are at x. Using Kp = Kc(RT)ⁿ, where n represents the mole difference of gaseous products and reactants, we find n to equal 1 for this reaction. With R as the gas constant (8.314 J/mol K) and the temperature at 800 °C (1073 K), we substitute the values accordingly. Upon calculation, we find x = 0.005, which indicates the amount of calcium carbonate that dissociated or reacted, leading us to the reacted percentage.
