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Paul
1 month ago
15

Gina made a poster for plastic recycling week and included this information on her poster: What corrections should Gina make? Ch

eck all that apply. Gina should put “cellulose” under “Synthetic.” Gina should put “plastic” under “Natural.” Gina should put “rubber tires” under “Synthetic.” Gina should put “starch” under “Natural.” Gina should put “DNA” under “Synthetic.” Gina should put “nylon” under “Natural.”
Chemistry
2 answers:
eduard [2.7K]1 month ago
7 0

Response:

C and D

I hope this is helpful <3

castortr0y [3K]1 month ago
3 0
Gina ought to classify "rubber tires" as "Synthetic."<span> She should categorize "starch" under "Natural."</span>
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What is the molarity of a solution that contains 2.35 g of nh3 in 0.0500 l of solution?
castortr0y [3046]
Molarity is defined as the number of moles present in one liter of solution. Given the mass of NH₃ is 2.35 g and its molar mass is 17 g/mol, the moles of NH₃ in 2.35 g can be calculated as 2.35 g / 17 g/mol = 0.138 mol. Consequently, in a 0.05 L solution, the number of moles amounts to 0.138 mol. Therefore, the concentration in 1 L is: 0.138 mol / 0.05 L x 1L = 2.76 mol. Thus, the molarity of NH₃ is 2.76 M.
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1 month ago
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The first eighteen chemical elements on the periodic table are described below in a series of statements. The first 1S letters o
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The question appears to be confusing. The periodic table consists of elements organized by increasing atomic number.
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1 month ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
VMariaS [2998]

Result:

94.7 %

Explanation:

The balanced reaction is:

2 S + 3 O₂ → 2 SO₃

The stoichiometric mole ratio is:

S: 2 moles

O₂: 3 moles

Moles are calculated as mass divided by molar mass:

n = w / m

where n = moles, w = mass, m = molar mass.

Given:

For sulfur: w = 6.0 g, molar mass = 32 g/mol, so n = 6 / 32 = 0.1871 mol

For oxygen: w = 5.0 g, molar mass = 32 g/mol, thus n = 5 / 32 = 0.15625 mol

Comparing to stoichiometric ratios, sulfur is in excess, so oxygen is the limiting reagent, controlling product formation.

Using proportions:

3 mol O₂ produce 2 mol SO₃, so 1 mol O₂ yields 2/3 mol SO₃.

Therefore, 0.15625 mol O₂ yields (2/3) × 0.15625 = 0.1042 mol SO₃.

Mass of SO₃ produced = n × molar mass = 0.1042 mol × 80 g/mol = 8.340 g

The percentage yield is actual yield divided by theoretical yield times 100:

Percent yield = (7.9 g / 8.340 g) × 100 = 94.7 %

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3 months ago
Name one manufactured device or natural phenomenon that emits electromagnetic radiation in each of the following wavelengths: ra
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Based on the entries in the following table, which element is most commonly bonded to the acidic hydrogen? table some weak acids
lorasvet [2795]
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