The result will be 100.60 because we are adding to the atmosphere, which connects to the lubricator, and then it turns, resulting in 100.60.
Answer: 13 liters
Explanation: It is crucial to remember two factors that allow us to carry out this calculation.
Firstly, temperature and pressure must remain unchanged, so these constant values are not considered when calculating volume since they will always be the same.
Secondly, we are dealing with the same gas, with the conditions remaining consistent. Hence, we can proceed.
For 1.2 moles of gas, we have a volume of 8.5 liters. Now, let's determine the volume for 0.65 moles:
0.65 mole * (8.5 liter / 1.2 mole) = 4.25 liters
As we maintain the same gas type, we simply need to total the volumes for each mole amount:
8.5 liters + 4.25 liters = 12.75 liters, which rounds to 13 liters.
In order to respond to this query, one must understand the molecular structure of the compound. Molecular geometry is specific to particular compounds. For H₂O, the bond angle measures 109.5°. Conversely, H₃O⁺ has a bond angle that ranges between 104.5° and 109.5°. Thus, H₃O⁺ possesses the smaller bond angle.
15.9 KJ/mol Explanation: Given data: Temperature = T1 = 307 K, Temperature = T2 = 343 K, Gas constant R = 8.314 J/(mol • K), rate constant = k2/K1 = 89. To determine: Activation energy (in kJ/mol) = Ea =? Formula: The Arrhenius equation establishes the relationship between temperature and reaction rates. Here, in this equation, k = the rate constant, Ea = the activation energy, R = the Universal Gas Constant, T = the temperature. Solution: ln 89 = Ea / 8.314 J/mol.K * (0.0325 - 0.00291). then ln 89 = Ea / 8.314 J/mol.K * (2.95 x 10^2). Resulting in 4.488 = Ea / 8.314 J/mol.K * (2.95 x 10^2). Therefore, Ea = 4.488 * (2.95 x 10^2) / 8.314 J/mol.K which simplifies to Ea = 0.1324 / 8.314. Thus, Ea = 0.0159 and finally, Ea = 1.59 x 10^2 J/mol or 15.9 KJ/mol.
Response:
0.125 moles
Explanation:
According to Avogadro's principle, one mole of any substance contains 6.02x10^23 atoms.
This implies that 1 mole of chromium consists of 6.02x10^23 atoms.
Therefore, if 1 mole of chromium corresponds to 6.02x10^23 atoms,
Then X moles of chromium are equivalent to 7.52x10^22 atoms, thus
X moles of chromium = 7.52x10^22/6.02x10^23
Thus, X moles of chromium = 0.125 moles
Consequently, 0.125 moles of chromium contain 7.52x10^22 atoms
