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1 month ago

Benzene, C6H6, reacts with oxygen, O2, to form CO2 and H2O. How much O2 is required for the complete combustion of 1.0 mol C6H6?

2 answers:

4 0

C6H6 + O2 produces CO2 + H2O
Complete with coefficients for balance
C6H6 + 15/2 O2 leads to 6 CO2 + 3 H2O
You retain only necessary information
C6H6 15/2 O2
1 mol for 15/2 or 7.5 mol

15/2 or 7.5 mol O2 is needed.

;)

lorasvet [2.6K]1 month ago

3 0

Answer:

It is necessary to have 7.5 mol of oxygen

Explanation:

Hello, as mentioned, this represents a combustion reaction involving benzene:

$C_6H_6(l) + O_2(g) \longrightarrow CO_2 (g) + H_2O (g)$

The initial task is to balance the equation:

1 mol of $CO_2$ for each carbon in the benzene

1 mol of $H_2O$ for every two hydrogens in the benzene

1 mol of $O_2$ for each $CO_2$ and 0.5 mol for each $H_2O$

Balanced:

$C_6H_6(l) + 15/2 O_2(g) \longrightarrow 6 CO_2 (g) + 3 H_2O (g)$

Following the reaction:

For 1 mol of benzene, 15/2 (7.5) mol of oxygen is necessary.

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17 days ago

Explain why CaCl2 is likely to have properties similar to those of CaBr2

Alekssandra [2904]

Answer:

Both CaCl2 and CaBr2 consist of elements (bromine and chlorine) from the same group (group 7).

Explanation:

In the periodic table, elements are arranged into groups based on their valence electron count in the outermost shell. Elements in the same group, which possess a similar number of valence electrons, typically exhibit similar chemical behaviors.

Chlorine and Bromine in CaCl2 and CaBr2 belong to group 7, known as HALOGENS, characterized by having 7 valence electrons in their outer shell.

The similarity in properties between CaCl2 and CaBr2 arises because both contain Chlorine and Bromine, leading to analogous reactions and behaviors when interacting with other compounds.

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1 month ago

A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h

lions [2782]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution: 0.0328 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}$

The amount of HCl in the 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution: 0.0245 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}$

The amount of NaOH in the 0.100 L solution = 0.00245 moles

3) Determining the concentration of hydrochloric acid in the final solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl from the original 0.0082 moles of HCl.

The total volume of the mixture becomes 0.100 L + 0.250 L = 0.350 L

Remaining moles of unreacted HCl = 0.0082 moles - 0.00245 moles = 0.00575 moles

$Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}$

Concentration of the remaining HCl: $\frac{0.00575 moles}{0.350L}=0.0164 M$

0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0

28 days ago

From this list, choose all of the ionic compounds. Check all that apply. View Available Hint(s) Check all that apply. POCl3 KOCH

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Answer: $KOCH_2CH_3$ , $CH_3CH_2COONa$ , NaOH are all ionic compounds.

Explanation:

Ionic compounds form when one atom transfers its valence electrons to another atom, resulting in partial opposite charges on the participating atoms, which creates a strong attractive force between them.

An ionic bond is typically established between a metal and a non-metal.

For instance, $KOCH_2CH_3$ , $CH_3CH_2COONa$ , NaOH are all ionic compounds.

Conversely, a covalent compound arises through the sharing of electrons among the atoms involved, where generally a non-metal bonds with the same or another non-metal.

For example, $POCl_{3}$ , $SOCl_{2}$ etc are all covalent compounds.

Therefore, we can affirm that $KOCH_2CH_3$ , [tex]CH_3CH_2COONa, NaOH are indeed ionic compounds.

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1 month ago

Using the equation pH = -log [H+], determine the pH of a solution with a hydrogen ion concentration, or [H+], of 1x10-5. HINT: l

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Response:

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