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ira
3 months ago
12

Determine the torque applied to the shaft of a car that transmits 225 hp

Physics
1 answer:
Keith_Richards [3.2K]3 months ago
8 0

Incomplete query. The complete inquiry is as follows

Calculate the torque exerted on the shaft of a vehicle transmitting 225 hp at a rotation speed of 3000 rpm.

Response:

Torque=0.51 Btu

Analysis:

Given Information

Power=225 hp

Revolutions =3000 rpm

To determine

T( torque )=?

Process

As an object is moved by force over a distance, work is performed on that object. Similarly, when torque rotates an object through an angle, work is also accomplished.

T(Torque)=\frac{W(Work)}{2\pi n(Revolutions) }

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Answer:

This assertion is inaccurate.

Explanation:

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In contrast, the separation among electrons is primarily influenced by repulsive forces, not random movement as in gases. Electrons maintain distance as a result of repulsion between similarly charged particles. Therefore, the arrangement of electrons on a charged copper sphere occurs not from a random distribution but rather due to repulsion, establishing a set distance between them.

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Marcia is given an incomplete chemical equation that includes the number of nitrogen atoms present in the products of the reacti
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3 months ago
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A vector A is added to B=6i-8j. The resultant vector is in the positive x direction and has a magnitude equal to A . What is the
Yuliya22 [3333]

The answer is letter d, 8.3.

 

Here’s a solution for the given problem:

 

We have:

B = 6i - 8j 


Let A be unknown; we'll denote A as = mi + nj 



The resultant A+B lies along the x-axis (which implies A+B = Ki + 0j, where K is yet to be determined,

 

and we also know the magnitude of A+B is equivalent to the magnitude of A,

 

therefore, mag(A+B)=K=sqrt(m^2+n^2), or K^2 = m^2+n^2. 



Using vector addition, A+B becomes (m+6)i + (n-8)j.

 

Since we know A+B = Ki + 0j, we can establish that: 

m + 6 = K 


n - 8 = 0, which gives n=8. 

Thus, K^2=m^2+n^2 means (m+6)^2 = m^2 +8^2 


= m^2 + 12m + 36 = m^2 + 64 


which gives us 12m = 28 


m = 2.33333... 

Consequently, the magnitude of A is sqrt[(2.333...)^2 + 8^2] = 8.3333.

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3 months ago
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