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mars1129
16 days ago
6

Imagine you are riding on a yacht in the ocean and traveling at 20 mph. You then hit a golf ball at 100 mph from the deck of the

yacht. You see the ball move away from you at 100mph, while a person standing on a near by beach would observe your golf ball traveling at 120 mph (20 mph + 100 mph).
Now imagine you are aboard the Hermes spacecraft traveling at 0.1c (1/10 the speed of light) past Mars and shine a laser from the front of the ship. You would see the light traveling at c (the speed of light) away from your ship. According to Einstein’s special relativity, how fast will a person on Mars observe the light to be traveling?


A) 0.1c (1/10 the speed of light)

B) c (the speed of light)

C)1.1c (c+0.1c)
Physics
2 answers:
ValentinkaMS [2.4K]16 days ago
4 0

As per Einstein's theory of special relativity, the light speed in a vacuum remains constant regardless of the observer's speed. Therefore, the response should be A) 0.1c (one-tenth the speed of light)

Yuliya22 [2.4K]16 days ago
4 0

Answer:

B) c (the speed of light)

Explanation:

When considering the golf ball's speed alongside that of the yacht, classical mechanics permits this addition.

However, light's photons do not conform to classical mechanics.

Einstein's assertion states that light's speed is invariant across all reference frames, independent of observer movement. It represents the utmost velocity achievable by any object.

Thus, to those onboard the Hermes spacecraft, the laser appears to travel at c (the speed of light), and the same applies for observers on Mars.

Inside the Hermes, time dilation ensures that no entity exceeds the speed of light.

Let T_{o} symbolize the interval measured on the Hermes,

Time outside Hermes

T = \frac{T_{o}}{\sqrt{1-\frac{v^{2} }{c^{2} } } } \\\\T = \frac{T_{o}}{\sqrt{1-\frac{(0.1c)^{2} }{c^{2} } } } \\\\T = 1.005T_{o}

Hence, one second on Hermes equates to 1.005 seconds outside, showing that the laser seems to propagate at light speed for both observers inside and outside the spacecraft.

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1. Use Coulomb’s Law (equation below) to calculate the approximate force felt by an electron at point A in the schematic below.
Keith_Richards [2256]

Answer:

Explanation:

The data indicates that point A is located midway between two charges.

To calculate the electric field at point A, we begin with the field produced by charge -Q ( 6e⁻ ) at A:

= 9 x 10⁹ x 6 x 1.6 x 10⁻¹⁹ / (2.5)² x 10⁻⁴

= 13.82 x 10⁻⁶ N/C

This field points towards Q⁻.

A similar field will arise from the charge Q⁺, but it will direct away from Q⁺ toward Q⁻.

To find the resultant field, we add these contributions:

= 2 x 13.82 x 10⁻⁶

= 27.64 x 10⁻⁶ N/C

For the force acting on an electron placed at A:

= charge x field

= 1.6 x 10⁻¹⁹ x 27.64 x 10⁻⁶

= 44.22 x 10⁻²⁵ N

8 0
17 days ago
A copper sphere was moving at 25 m/s when it hit another object. This caused all of the KE to be converted into thermal energy f
kicyunya [2264]

Answer:

\Delta T = 0.81 ^oC

Explanation:

According to the principle of energy conservation

all kinetic energy will change into thermal energy to increase its temperature

\frac{1}{2}mv^2 = ms\Delta T

Next, divide both sides by the object's mass

\frac{1}{2}v^2 = s\Delta T

the resulting temperature change is expressed as

\Delta T = \frac{v^2}{2s}

\Delta T = \frac{25^2}{2\times 387}

\Delta T = 0.81^oC

3 0
12 days ago
Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling backward with a
ValentinkaMS [2425]

Conclusion:

The total net force acting on the objects is 16 N, directed towards the right.

Clarification:

It is stated that,

The force exerted by the dog, F_1 = 32\ N (to the right)

The force exerted by Simone, F_2 = -16\ N (backward)

Here, assume the backward direction is negative and the right direction is positive.

The net force will move in the direction where the larger force is present. The net force can be calculated as:

F=F_1+F_2

F=32+(-16)

F = 16 N

Thus, the net force amounts to 16 N, acting towards the right.

6 0
24 days ago
Read 2 more answers
Which pair of graphs represent the same motion of an object
Ostrovityanka [2204]
The correct choice is C
3 0
1 month ago
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A metal, M, forms an oxide having the formula M2O3 containing 52.92% metal by mass. Determine the atomic weight in g/mole of the
ValentinkaMS [2425]

Answer:

The molar mass of the metal in grams per mole is calculated to be 8.87.

Explanation:

Initially, we can consider a sample of the compound weighing 100 g. This results in:

  • 52.92% metal: 52.92 g M
  • 47.80% oxygen: 47.80 g O

 By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:

moles of oxygen=\frac{47.8g*1mol}{16g}

moles of oxygen=2.9875

The formula for the metal oxide indicates that:

2 M⁺³ + 3 O²⁻ ⇒ M₂O₃

From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

2.9875 moles of oxygen*\frac{2 moles of metal M}{1 mol of oxygen} = 5.975 moles of metal M

Given 52.92 g of metal in the sample, the molar mass of the metal is:

molar mass=\frac{52.92 g}{5.975 mol}

molar mass≅ 8.87 g/mol

The molar mass of the metal in grams per mole is 8.87.

The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.

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