Consider the graph and equation, y = 3x, that represent Alonso’s walking speed. What relationship is represented by this equatio

Answer: 47/59

Step-by-step explanation:

1 product = $65.00
20 products = 65 x 20 = $1300

Sales Tax is 3.5% of $1300 = 0.035 x $1300 = $45.50

Grand total = $1300 + $45.50 = $1345.50

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Response: $1345.50
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Answer:

i) A total of 40320 different arrangements

ii) For the initial 3 spots, there are 336 different combinations.

Step-by-step explanation:

Given: The total finalists = 8

The count of boys = 3

The count of girls = 5

To determine the number of sample point in the sample space S for possible arrangements, we calculate the factorial of 8!

The number of possible arrangements equals 8!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

= 40320

ii) Among the 8 finalists, we must select the first 3 spots. The sequence matters, hence we utilize permutation.

nPr =

Here n = 8 and r = 3

Substituting n = 8 and r = 3 into the formula, we arrive at

8P3 =

=

= 6.7.8

= 336

Thus, there are 336 different arrangements for the first 3 spots.

Answer:

Step-by-step explanation:

Let the number of cans collected by Shane be x.

Thus, the number of cans collected by Abha is x + 178.

Given that a minimum of 2000 cans is required to be collected.

Therefore, we have the inequality,[ [TAG_19]]

Total cans by Shane + Total cans by Abha ≥ 2000.

That is,

Thus, the necessary inequality is .

Hello!

Before you tackle any problems, it's essential to designate which scenario represents event A and which corresponds to event B. I usually follow the order they are presented in the question, so:

A = S<span>tudent participates in student council
B = S</span><span>tudent participates in after school sports

Any problem that mentions "given" in the question will need to refer to </span>P(A | B)<span> = P(</span>A ∩ B)/P(B). P(A | B) essentially represents the "probability of event A, given that event B has occurred." Meanwhile, P(A ∩ B) denotes the likelihood of both A and B taking place, while P(B) signifies just the probability of event B happening. All required information has been provided, so:

P(A | B) = P(A ∩ B)/P(B)
P(A | B) = 11% / 62%
P(A | B) = 0.11 / 0.62
P(A | B) = 0.18

Thus, there is approximately an 18% probability that <span>a student is involved in student council, given participation in after school sports.

I hope this was helpful!:-)</span>