1,107 cc
The scanning consists of 10 intervals:
[0,1.5), [1.5,3), [3,4.5), [4.5,6), [6,7.5), [7.5,9), [9,10.5), [10.5,12), [12,13.5), [13.5,15)
To estimate the volume using the Midpoint Rule, n should be set to 10.
Given that we will use n=5, we will split the range [0,15] into five intervals of lengths 3 each:
[0,3], [3,6], [6,9], [9,12], [12,15] and calculate their midpoints:
1.5, 4.5, 7.5, 10.5, and 13.5.
Next, we will determine the volume V from the five cylinders, where each has a height h=3 and the base area A corresponds to the calculated midpoints' intervals:
Cylinder 1
Midpoint=1.5, corresponding to the 2nd interval
A = 18, V= height * area of the base = 18*3 = 54 cc
Cylinder 2
Midpoint=4.5, corresponding to the 4th interval
A = 78, V= height * area of the base = 78*3 = 234 cc
Cylinder 3
Midpoint=7.5, corresponding to the 6th interval
A = 106, V= height * area of the base = 106*3 = 318 cc
Cylinder 4
Midpoint=10.5, corresponding to the 8th interval
A = 129, V= height * area of the base = 129*3 = 387 cc
Cylinder 5
Midpoint=13.5, corresponding to the 10th interval
A = 38, V= height * area of the base = 38*3 = 114 cc
Thus, the estimated volume is
54 + 234 + 318 + 387 + 114 = 1,107
Answer:
(A) Approximately normal with a mean of $206,274 and a standard deviation of $3,788.
Step-by-step explanation:
The Central Limit Theorem asserts that for a random variable X that follows a normal distribution with a mean of 
and a standard deviation of 
, the sampling distribution of sample means, when drawn with size n, can be estimated as a normal distribution with a mean of and a standard deviation of 
.
Even if the variable is skewed, as long as n is no less than 30, the Central Limit Theorem still holds.
Population:
Right skewed
Mean $206,274
Standard deviation $37,881.
Sample:
<pbased on="" the="" central="" limit="" theorem="" it="" can="" be="" approximated="" to="" normal.="">
Mean $206,274
Standard deviation 
So the correct answer is:
(A) Approximately normal with a mean of $206,274 and a standard deviation of $3,788.
</pbased>
First, you need to convert everything to a single unit. For this example, I'll use fractions.
75% = 3/4
680/1 * 3/4
Cross Multiply
2040/4
Reduce
510
The mayor garnered 510 votes.
Assuming the cost of 1 liter of milk is x$
and the cost of 1 loaf of bread is y$
Based on the information provided
the equations are 333x + 555y = 11
and 444x + 444y = 10
By subtracting these expressions,
we derive
(333x + 555y = 11) * 444
(444x + 444y = 10) * 333
(-) (-) (-)
147852x + 246420y = 4884
147852x + 147852y = 3330
(-) (-) (-)
------------------------------
98568y = 1554
y = 1554/98568
= 0.0157$
= 0.02$
Cost of 1 loaf of bread is 2 cents
Substituting the value of y back in
333x + 555*0.0157 = 11333x + 8.7135 = 11333x = 2.2865x = 2.2865/333x = 0.00068$ = 0.01$
Cost of 1 liter of milk = 1 cent
1.5
