Tear gas has the composition 40.25% carbon, 6.19% hydrogen, 8.94% oxygen, 44.62% bromine. what is the empirical formula of this

To determine the specific heat capacity of the metal and assist in its identification, the heat absorbed by the calorimeter can be computed using: Energy = mass * specific heat capacity * temperature change Q = 250 * 1.035 * (11.08 - 10) Q = 279.45 cal/g. Next, we employ the same formula for the metal because the heat taken in by the calorimeter should equal the heat expelled by the metal. -279.45 = 50 * c * (11.08 - 45) [the minus sign indicates energy release] solving for c gives us 0.165. Therefore, the specific heat capacity of the metal amounts to 0.165 cal/g°C.

The oxidation state numbercan aid in identifying the unknown element present in both compounds. They denote the number of electrons that are either donated, received, or shared to yield compounds.

Remember the fundamental principles governing oxidation numbers.

1. In a neutral compound, the total of all oxidation numbers is zero.
2. Chlorine, bromine, and iodine typically exhibit an oxidation number of -1(unless paired with fluorine and oxygen)

Assume the oxidation state for element Mis designated as x.
Referring to rule 2, chlorine possesses an oxidation state of -1.

Now, for the compound MCl₂ (which is neutral), the equation can be formulated as
x + (2 * -1)= 0 ⇒ x₁= +2

For MCl₃, the corresponding equation is
x + (3 * -1)=  0 ⇒ x₂= +3

This indicates that the elementhas two distinct oxidation statesin its compounds, which are +2and +3.

The identified element is iron (Fe), as it shows +2 and +3 oxidation states across these compounds.

Memorizing this is essential. Regrettably, there isn't a simpler method to tackle these oxidation states.

The final answer is iron (Fe).

Clarification:

The pertinent information is outlined as follows.

m = 10.0 kg = 10,000 g (since 1 kg = 1000 g)

Starting temperature of block 1, = (100 + 273) K = 373 K

Starting temperature of block 2, = (0 + 273) K = 273 K

Therefore, the heat lost by block 1 equals the heat received by block 2

It's important to convert the temperature into Kelvin as (50 + 273) K = 323 K.

Additionally, the relationship between enthalpy and temperature change is as follows.

=

= 1243550 J

or, = 1243.5 kJ

Next, determine the entropy change for block 1 as follows.

=

=

= -554.12 J/K

Now, the entropy change for block 2 is as follows.

   

           =

           =

           = 647.49 J/K

Thus, the total entropy is the sum of the entropy changes of both blocks.

                   = -554.12 J/K + 647.49 J/K

           = 93.37 J/K

In conclusion, for this reaction, the outcome is 1243.5 kJ and is 93.37 J/K.