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Wittaler
2 months ago
7

A typical deposit of cholesterol,C27H460,in an artery has a mass of 3.90mg.how many molecules of cholesterol are present in this

deposit?
Chemistry
1 answer:
Anarel [2.9K]2 months ago
8 0
The quantity is 6.074 X 10¹⁸ molecules. To calculate the molecular weight (MM) of the compound C₂₇H₄₆O, we use the formula: 27*(MM of C) + 46*(MM of H) + (MM of O). This leads to: 27*(12.0107) + 46* (1.00784) + (15.999) = 324.2889 + 46.36064 + 15.999 = 386.64854 g. The molar mass of any compound indicates the number of molecules found in one mole, which is 6.022 X 10²³ (Avogadro's number). So, if 386.64854 g of C₂₇H₄₆O consists of 6.022 X 10²³ cholesterol molecules, we can determine how many molecules are found in a deposit of 3.9mg or 0.0039g of C₂₇H₄₆O by using the unitary method. Number of molecules = 6.074 X 10¹⁸ molecules.
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3.51e23 atoms Fe= g Fe
VMariaS [2998]

Answer:

Mass of Fe = 32.55 g

Explanation:

The molar mass of a single Fe atom is 55.845 g/mol

This means that

1 mole of Fe equals = 55.845 g ..............(1)

According to the mole concept,[ [TAG_24]]

1 mole of Fe contains = 6.022\times 10^{23}atom..........(2)

If we substitute 1 mole in equation (2) with 55.845 g, it becomes:

55.845 g of Fe contains = 6.022\times 10^{23} atoms

Reversing the equation yields

6.022\times 10^{23} atoms of Fe correspond to 55.845 g

1 atom of Fe corresponds to \frac{55.845}{6.022\times 10^{23}} g

3.51\times 10^{23} one atom corresponds to

\frac{55.845}{6.022\times 10^{23}}\times 3.51\times 10^{23}

On computation,

3.51\times 10^{23} one atom corresponds to 32.55 g of Fe

Mass of Fe = 32.55 g

7 0
2 months ago
If it takes 15 s for a certain sample of neon to effuse through a porous barrier, how much time will it take for the same amount
alisha [2963]

Answer:

The correct response is;

2. takes less than 15 seconds

Explanation:

Graham's law of effusion conveys that

\frac{Rate 1}{Rate2} =\sqrt{\frac{Molar Mass2}{MolarMass 1} }

Thus, knowing that the molar mass of neon gas = 20.18 g/mol

And, the molar mass of nitrogen gas = 28.014 g/mol

We deduce

= 0.72

\frac{Rate 1}{15} =\sqrt{\frac{20.18}{28.014} }So, the effusion rate of nitrogen gas will be 0.72*15 = 12.73 seconds, which is indeed less than 15 seconds.

5 0
1 month ago
Compaction is most significant as a lithification process for sedimentary rocks composed of sand-sized particles. True False
VMariaS [2998]

Response:

FALSE

Rationale:

Sedimentary rocks are defined as rocks formed through the processes of compaction and cementation. Initially, sediments derived from various locations must accumulate. Over time, these deposited sediments undergo substantial compaction due to the weight of the layers above. This process converts loose sediments into solid rock. This is the process through which sedimentary rocks, comprised of sand-sized particles, are formed. For instance, examples include Shale, Sandstone, and Mudstone.

Thus, both compaction and cementation are crucial in the formation of sedimentary rocks.

Therefore, the statement above is False.

8 0
2 months ago
An atom of beryllium (m = 8.00 u) splits into two atoms of helium (m = 4.00 u) with the release of 92.2 kev of energy. if the or
VMariaS [2998]
The energy released results in a kinetic energy of 92.2 keV for the products. We should convert keV into Joules, noting that 1 keV equals a kiloelectron volt. The required conversion is: 1.602×10⁻¹⁹ <span>joule = 1 eV

Kinetic energy = 92.2 keV * (1,000 eV/1 keV) * (</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules

Next, we can determine the velocity of each He atom from the kinetic energy:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
This solves to give us: v = 5.367×10¹¹ m/s
4 0
1 month ago
Read 2 more answers
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