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Wittaler
11 days ago
7

A typical deposit of cholesterol,C27H460,in an artery has a mass of 3.90mg.how many molecules of cholesterol are present in this

deposit?
Chemistry
1 answer:
Anarel [2.6K]11 days ago
8 0
The quantity is 6.074 X 10¹⁸ molecules. To calculate the molecular weight (MM) of the compound C₂₇H₄₆O, we use the formula: 27*(MM of C) + 46*(MM of H) + (MM of O). This leads to: 27*(12.0107) + 46* (1.00784) + (15.999) = 324.2889 + 46.36064 + 15.999 = 386.64854 g. The molar mass of any compound indicates the number of molecules found in one mole, which is 6.022 X 10²³ (Avogadro's number). So, if 386.64854 g of C₂₇H₄₆O consists of 6.022 X 10²³ cholesterol molecules, we can determine how many molecules are found in a deposit of 3.9mg or 0.0039g of C₂₇H₄₆O by using the unitary method. Number of molecules = 6.074 X 10¹⁸ molecules.
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A chamber with a fixed volume is shown above. The temperature of the gas inside the chamber before heating is 25.2 C and it’s pr
KiRa [2726]

Answer:

Explanation:

Given data:

Initial temperature T₁ = 25.2°C = 298.2K

Initial pressure P₁ = 0.6atm

Final temperature = 72.4°C = 345.4K

What we need to find:

Final pressure = ?

To determine this, we apply a modified version of the combined gas law with constant volume. This simplifies our calculations to:

\frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }

Here, P and T signify pressure and temperatures, 1 refers to initial and 2 to final temperatures.

Now we can substitute the known variables:

\frac{0.6}{298.2}   = \frac{P_{2} }{345.4}

P₂ = 0.7atm

3 0
1 month ago
From the following list of elements, those that will always form ionic compounds in a 1:2 ratio with zinc.
eduard [2520]
A. iodine C. fluorine F. bromine Explanation: Ionic bonds primarily form between metals and non-metals, typically where there exists a significant difference in electronegativity between the constituent atoms. This situation results in one atom seeking to gain electrons while the other donates them. For zinc to form a compound in a 1:2 ratio, its combining power must align accordingly. The prevalent oxidation state of zinc is +2. The other combining atoms must also possess the capacity to accept two electrons. The halogens fit perfectly here, as they require only one electron to achieve stability and are highly electronegative. Hence, if two halogens combine with zinc, they will result in an ionic bond. The relevant halogens include fluorine, chlorine, bromine, iodine, and astatine which will yield compounds: ZnF₂, ZnBr₂, and ZnI₂.
3 0
12 days ago
Arrange the sublevels in ascending order by the number of electrons they can contain. p sublevel s sublevel d sublevel f subleve
eduard [2520]

The electronic configuration of an atom details how electrons are organized across various shells and sublevels.

There are four categories of sublevels: s, p, d, and f. Each of these sublevels contains orbitals, which are regions with a high likelihood of containing an electron, with each orbital capable of holding a maximum of 2 electrons.

As a result,

s-sublevel possesses 1 orbital, allowing for a maximum of 2 electrons.

p-sublevel has 3 orbitals, accommodating a maximum of 6 electrons.

d-sublevel encompasses 5 orbitals, permitting a maximum of 10 electrons.

f-sublevel includes 7 orbitals, with a maximum of 14 electrons.

Therefore, the ascending order of sublevels based on the maximum number of electrons they can hold is:

s < p < d < f

3 0
27 days ago
Read 2 more answers
In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form
KiRa [2726]

I predict that there will be an increase in the seconds recorded in the time column. This is because, as more water is mixed with sodium thiosulfate, its concentration diminishes in each flask. Additionally, a lower concentration results in a slower reaction rate since fewer molecules of sodium thiosulfate means there are less frequent collisions with sulfuric acid. With fewer collisions occurring in the reaction, it takes a longer time for the reaction to complete, leading to increased time when sodium thiosulfate is diluted.

Explanation:

I can confirm that this explanation is accurate.

6 0
1 month ago
Calculate the molarity of a 10.0% (by mass) aqueous solution of hydrochloric acid.
VMariaS [2693]

The question is incomplete,the complete question:

Determine the molality of a 10.0% (by weight) solution of hydrochloric acid in water:

a) 0.274 m

b) 2.74 m

c) 3.05 m

d) 4.33 m

e) the solution's density is necessary for calculations

Answer:

The molality for a 10.0% (by weight) hydrochloric acid solution is 3.05 mol/kg.

Explanation:

The solution is a 10.0% (by weight) hydrochloric acid mix.

This means there are 10 grams of HCl in 100 grams of the solution.

Amount of HCl = 10 g

Total mass of solution = 100 g

Total mass of solution = Mass of solute + Mass of solvent

Mass of solvent (water) = 100 g - 10 g = 90 g

Calculate moles of HCl = \frac{10 g}{36.5 g/mol}=0.2740 mol

Mass of water converted to kilograms = 0.090 kg

Molality = \frac{0.2740 mol}{0.090 kg}=3.05 mol/kg

<strongTherefore, the molality of a 10.0% (by weight) hydrochloric acid solution is 3.05 mol/kg.

6 0
1 month ago
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