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forsale
2 months ago
11

Suppose a steam locomotive is rated at 7500 horsepower. If its efficiency is 6%, how much wood must be burned in a 3-hour trip?

1 hp = 750 W. Wood has an energy density of 20.0 MJ/ kg.
Engineering
1 answer:
choli [298]2 months ago
3 0
50,625 kg of wood. Power input can be calculated using power output divided by efficiency. The output is 7500 horsepower, which equates to 5625000 W. Given the efficiency of 6% (or 0.06), the input power is 93750000 W. Then, calculating the input energy over a 3-hour trip (10800 seconds), we find an energy input of 1.0125×10^12 J. Hence, the mass of wood required is the energy divided by its density of 20.0 MJ/kg, resulting in 50,625 kg.
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estimate the area for a landfill for 12000 p producing waste for 10 y. assume that the national average is
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1.015 ha.

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To calculate the landfill area required for 12,000 people producing waste over 10 years, follow these steps:[STEP ONE: Calculate the average solid waste generated per person per year (kg p^-1 ^y(kg/py)).

According to the problem, the average solid waste produced is 2.78 kg per person daily (kg/pd), hence converting to kg/py involves:

2.78 × 365 days = 1014.7 kg/py.

STEP TWO: Determine yearly volume of refuse per person.

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STEP THREE: Calculate total solid waste volume over 10 years for 12,000 individuals.

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STEP FOUR: Find the required area for the landfill.

Note: The total height for the landfill should be 20 + 4 = 24m.

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