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2 days ago

4.1 kg of a plastic, used to make plastic bottles, has a carbon footprint of 6.0 kg of carbon dioxide.

Chemistry

1 answer:

lorasvet [956]2 days ago

4 0

Response:

The carbon footprint associated with a plastic bottle weighing 23.5 g is 34.390 g.

Reasoning:

This can be calculated using a straightforward rule of three. Specifically:

$x = \frac{23.5\,g}{4100\,g}\times 6000\,g$

$x = 34.390\,g$

Hence, for a bottle of mass 23.5 g, the carbon footprint totals 34.390 g.

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The researcher performed a follow-up experiment to measure the rate of oxygen consumption by muscle and brain cells. Predict the

Alekssandra [968]

Answer:

Mitochondria are plentiful in mammalian cells, with their proportions varying across different tissues, from less than 1% in white blood cells to as high as 35% in heart muscle cells. It is essential to understand that mitochondria are not static structures but instead form a dynamic network that frequently undergoes processes of fission and fusion. In skeletal muscle, they exist as part of a reticular membrane network. The two subpopulations, subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria, occupy different subcellular regions and exhibit slight differences in their biochemical and functional characteristics tied to their anatomical context. The SS mitochondria are positioned just beneath the sarcolemma, while IMF mitochondria are found closely associated with myofibrils. Their distinct properties likely play a role in their adaptability. SS mitochondria make up about 10-15% of the total mitochondrial volume and are believed to be more adaptable than their IMF counterparts, despite the latter displaying higher levels of protein synthesis, enzyme activity, and respiration (1).

Explanation:

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16 days ago

Read 2 more answers

The speed of light in a vacuum is 2.998 × 10 8 8 m/s. How long does it take for light to circumnavigate the Earth, which has a c

castortr0y [923]

Answer:- 0.134 seconds

Solution:- The speed is given as $2.988*10^8\frac{m}{s}$ and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.

Unit conversion is needed from miles to meters since the speed is given in meters per second.

1 mile = 1609.34 meters

Thus, $24900mile(\frac{1609.34meter}{mile})$

= 40072566 meters

Now, $speed=\frac{distance}{time}$

Rearranged for time, that gives: $time=\frac{distance}{speed}$

Inserting the values:

$time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}$

= 0.134 seconds

Hence, light would take 0.134 seconds to traverse the indicated distance. The answer without the unit is 0.134.

8 0

4 days ago

In an experiment a student mixes a 50.0 mL sample of 0.100 M AgNO₃(aq) with a 50.0 mL sample of 0.100 M NaCl(aq) at 20.0°C in a

KiRa [971]

The enthalpy change associated with the precipitation reaction is 84 kJ/mole

Why?

The chemical equation for the reaction can be written as

AgNO₃(aq) + NaCl (aq) → AgCl(s) + NaNO₃(aq)

To determine the enthalpy change, the following equation applies

$\Delta H =\frac{Q}{n}$

To calculate the heat (Q):

$Q=m*C*\Delta T=(100g)*(4.2 J/g*^\circ C)*(21^\circ C-20^\circ C)\\\\Q=420J$

Next, we need to calculate the number of moles involved in the reaction (n):

$n=[AgNO_3]*v(L)=(0.1M)*(0.05L)=0.005moles$

With these two values, we can substitute them into the first equation:

$\Delta H= \frac{420J}{0.005moles}=84000J/mole=84kJ/mole$

Have a great day!

5 0

5 days ago

At 1.01 bar, how many moles of CO2 are released by raising the temperature of 1 litre of water from 20∘C to 25∘C

VMariaS [1037]

Answer: 0.0007 moles of $CO_2$ are released when the temperature rises.

Explanation:

To determine the moles, we utilize the ideal gas law, as follows:

$PV=nRT$

where,

P = gas pressure = 1.01 bar

V = gas volume = 1L

R = gas constant = $0.08314\text{ L bar }mol^{-1}K^{-1}$

Calculated moles at T = 20° C

The gas temperature = 20° C = (273 + 20)K = 293K

Substituting values into the equation gives:

$1.01bar\times 1L=n_1\times 0.0814\text{ L bar }mol^{-1}K^{-1}\times 293K\\n_1=0.04146moles$

Calculated moles at T = 25° C

The gas temperature = 25° C = (273 + 25)K = 298K

Substituting values into the equation gives:

$1.01bar\times 1L=n_2\times 0.0814\text{ L bar }mol^{-1}K^{-1}\times 298K\\n_2=0.04076moles$

Released moles = $n_1-n_2=0.04146-0.04076=0.0007moles$

Therefore, 0.0007 moles of $CO_2$ are released when the temperature increases from 20° C to 25° C.

5 0

13 days ago

A food worker had safely cooled a large pot of soup to 70 F (21 C) with two hours. What temperature must the soup Reach in the f

lorasvet [956]

After four hours of cooling, the soup reached a temperature of 140 F (or) 42 C.

Explanation:

A food worker allowed a cup of soup to cool for two hours,

step 1: The temperature attained in two hours is 70 F (or) 21 C

step 2: Consequently, in four hours, this doubles the value

Therefore, the temperature after four hours is 2(70)= 140 F (or) 2(21)= 42 C

4 0

11 days ago