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3 months ago

4.1 kg of a plastic, used to make plastic bottles, has a carbon footprint of 6.0 kg of carbon dioxide.

Chemistry

1 answer:

lorasvet [2.7K]3 months ago

4 0

Response:

The carbon footprint associated with a plastic bottle weighing 23.5 g is 34.390 g.

Reasoning:

This can be calculated using a straightforward rule of three. Specifically:

$x = \frac{23.5\,g}{4100\,g}\times 6000\,g$

$x = 34.390\,g$

Hence, for a bottle of mass 23.5 g, the carbon footprint totals 34.390 g.

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Calculate the mass, in grams, of a single tellurium atom (mte = 127.60 amu ).

castortr0y [3046]

1 atomic mass unit (amu) represents the mass of an atom or is used to measure mass on an atomic scale. It is also referred to as a dalton, abbreviated as Da, while atomic mass unit is indicated as amu.

1 amu can be translated into grams as follows:

$1 amu = 1.6 * 10^-2^4 g$

$Mass of Te = 127.6 amu$

For conversion into grams:

$M = (127.6 ) * 1.6 * 10^-2^4 g$

$M = 204.16 * 10^-2^4 g$

Therefore, the mass of Te is 204.16 * 10^-2^4 g

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3 months ago

Read 2 more answers

H2PO4-(aq) ⇆ H+(aq) + HPO42-( which ion plays the role of hydrogen ion donor and which one plays the hydrogen ion acceptor in BP

lions [2927]

H2PO4- acts as a proton donor, whereas HPO42- serves as a proton acceptor. Step 1: Determining hydrogen ion donors and acceptors in the reaction displayed: H2PO4- is predisposed to release a H+ ion to yield HPO42-. On the other hand, HPO42- is inclined to accept a H+ ion, producing H2PO4-. The process of an acid in a water solvent is characterized as dissociation: HA ⇔ H+ + A- where HA denotes a proton acid. Therefore, H2PO4- = HA and HPO42- = A-. Acids are recognized as proton donors, which is why H2PO4- donates protons and HPO42- accepts them.

6 0

3 months ago

Valproic acid, used to treat seizures and bipolar disorder, is composed of C, H, and O. A 0.165-g sample is combusted to produce

VMariaS [2998]

Answer:

The empirical formula is = $C_4H_8O$

The Valproic acid formula is = $C_8H_{16}O_2$

Explanation:

Mass of the produced water = 0.166 g

Molar mass of water = 18 g/mol

The moles of $H_2O$ are calculated as 0.166 g /18 g/mol = 0.00922 moles.

In 1 mole of water, there are 2 moles of hydrogen atoms.

Thus,

Moles of H = 2 x 0.00922 = 0.01844 moles

Each hydrogen atom's molar mass is 1.008 g/mol.

Hydrogen mass in the molecule = 0.01844 x 1.008 = 0.018588 g

Mass of produced carbon dioxide = 0.403 g

Molar mass of carbon dioxide = 44.01 g/mol

The moles of $CO_2$ are calculated as 0.403 g /44.01 g/mol = 0.009157 moles.

Each carbon atom's presence is 1 mole in 1 mole of carbon dioxide.

So,

Moles of C = 0.009157 moles

The molar mass of carbon is 12.0107 g/mol.

Carbon mass in molecule = 0.009157 x 12.0107 = 0.11 g

Since Valproic acid comprises only hydrogen, oxygen, and carbon, the oxygen mass in the sample = Total mass - Carbon mass - Hydrogen mass.

The sample's overall mass = 0.165 g.

Oxygen mass in the sample = 0.165 - 0.11 - 0.018588 = 0.036412 g

The molar mass of oxygen is 15.999 g/mol.

Moles of O = 0.036412 / 15.999 = 0.002276 moles

Taking the simplest ratio for H, O, and C yields:

0.01844: 0.002276: 0.009157

= 8: 1: 4

The empirical formula becomes $C_4H_8O$

While molecular formulas detail the precise count of atoms for each element, empirical formulas represent the simplest form or reduced ratio of these elements in the compound.

Consequently,

The molecular mass equals n × Empirical mass.

Here, n is a positive integer from 1, 2, 3...

Empirical mass = 4×12 + 8×1 + 16 = 72 g/mol.

Molar mass = 144 g/mol.

Thus,

The molecular mass = n × Empirical mass.

144 = n × 72

⇒ n = 2

The Valproic acid formula is = $C_8H_{16}O_2$

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3 months ago