Answer:
a) 
b) 1657 €
Explanation:
Hola,
a) En esta cuestión analizaremos el millón de litros de agua anualmente, dado que este dato nos permite calcular el calor necesario para calentar dicha cantidad, considerando que la densidad del agua es de 1 kg/L:
A continuación, utilizamos la entalpía de combustión del metano para determinar la cantidad en kilogramos necesaria, ya que la energía calórica perdida por el metano es equivalente a la energía obtenida por el agua:
b) En este supuesto, tenemos que, bajo condiciones normales de 1 bar y 273 K, el precio de 1 metro cúbico de metano es 0,45 €, lo que nos permite calcular las moles de metano en esas condiciones:
En consecuencia, los kilogramos de metano que se obtienen por 0,45 € son:
Finalmente, usando regla de tres:
0.715 kg ⇒ 0.45 €
2630 kg ⇒ X
X = (2630 kg x 0.45 €) / 0.715 kg
X = 1657 €
Regards.
Answer:
0.31%
Explanation:
For the chemical reaction:
I₂ + 2 S₂O₃²⁻ → 2 I⁻ + S₄O₆²⁻
0.043 L multiplied by 0.117 M of sodium thiosulfate gives 5.031x10⁻³ moles of S₂O₃²⁻
5.031x10⁻³ moles of S₂O₃²⁻ produces:
ClO⁻⁻ + 2 H⁺ + 2 I⁻ → I₂ + Cl⁻ + H2O
2.5156x10⁻³ moles of I₂ equates to moles of NaClO
2.5156x10⁻³ moles of NaClO times 
yields 0.187 g of NaClO
Thus, the mass percentage composition is:
= 0.31%
I hope this helps!
The density is 1.03 g/cm³.
Explanation: The density of a substance is calculated with the formula:
1 kg = 1000 g therefore 2.06 kg = 2060 g.
1 L = 1000 cm³ thus 2 L = 2000 cm³.
We now find:
Mass = 2060 g
Volume = 2000 cm³.
Thus, the final answer of density is:
1.03 g/cm³.
I hope this information assists you.
While the original inquiry is incomplete, the comprehensive question is:
Many chemicals can illustrate spots on a TLC plate that have been processed and dried. The permanganate used in the video creates yellow spots against a purplish background, taking advantage of the oxidizing capability of basic permanganate (MnO4), which outperforms chromic acid as an oxidizing agent. Chromic acid can also be employed to visualize spots, resulting in a green hue on the yellow background, indicating oxidation. So, can chromic acid be conveniently used to visualize spots when tracking a reaction converting an alcohol into a ketone? What observations are anticipated if one attempts this? Furthermore, if a small amount of alcohol is included in a solvent mixture for eluting your TLC plate, why must the plate be fully dried before visualizing the spots with an oxidizing agent like permanganate or chromic acid?
Answer:
Typically, using chromic acid to visualize spots during the conversion of alcohol to ketone is not feasible. The alcohol (substrate) will convert into its respective ketone due to the presence of chromic acid, causing the spots for the product and the reactant to align horizontally. This alignment complicates differentiation between the spots, making chromic acid unsuitable for this purpose.
It's vital to ensure that the plate is completely dry before observing spots with an oxidizing agent, even if alcohol is present in the solvent mixture. Incomplete drying could lead to oxidation of the alcohol by the oxidizing agent, resulting in transformation to carboxylic acid or ketone, thereby creating a new spot.
