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Lera25
2 months ago
12

How many lead (Pb) atoms will be generated when 5.38 moles of ammonia react according to the following equation: 3PbO+2NH3→3Pb+N

2+3H2O?
A) 1.62 × 10^24
B) 4.86 × 10^23
C) 2.43 × 10^24
D) 4.86 × 10^24
Chemistry
2 answers:
KiRa [2.9K]2 months ago
8 0

Answer:

4.86×10^23 lead molecules

Explanation:

castortr0y [3K]2 months ago
4 0

Answer:

4.86×10^23 lead molecules

Explanation:

Using the provided equation, 2 moles of ammonia produces 3 moles of lead.

Thus:

2 mol NH3/ 3 mol Pb

By utilizing this proportion, we can calculate the quantities for each molecule. For 5.38 mol NH3:

(5.38 NH3)(3 Pb/ 2 NH3) = (5.38)(3/2) mol Pb = 8.07 mol Pb

Next, we will apply Avogadro's number to determine the total number of molecules.

(8.07)(6.02×10^23) = 4.86×10^23 lead molecules

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2 months ago
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Answer:

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Explanation:

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Greetings!

The result is:

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