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insens350
1 month ago
7

Magnesium has an atomic mass of 24.3. there are two isotopes of magnesium - one contains 12 neutrons and the other contains 13 n

eutrons in the nucleus. what is the fractional abundance of the one that contains 12 neutrons?
Chemistry
1 answer:
KiRa [2.9K]1 month ago
3 0
From our knowledge:
-Atomic Mass = Protons + Neutrons
-Atomic Number equates to protons

Magnesium possesses an atomic number of 12, indicating that its naturally occurring isotope is Mg-12 (with 12 protons and 12 neutrons). In total, the atomic mass amounts to 24 amu. If we add another neutron to create Mg-13, the atomic mass will be 25 amu.

We can express this situation mathematically:
(amu of isotope 1)x + (amu of isotope 2)(x-1) = Average atomic mass
Here, isotope 1 represents the fractional abundance we're determining.

When substituted, it looks as follows:
24x + 25(1-x) = 24.3

Now let’s solve for x:
24x + 25 - 25x = 24.3
-x + 25 = 24.3
-x = -0.7
x = 0.7

Thus, the fractional abundance of Mg-12 is 0.7, or 70%.<span />
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3.51e23 atoms Fe= g Fe
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Mass of Fe = 32.55 g

Explanation:

The molar mass of a single Fe atom is 55.845 g/mol

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1 mole of Fe equals = 55.845 g ..............(1)

According to the mole concept,[ [TAG_24]]

1 mole of Fe contains = 6.022\times 10^{23}atom..........(2)

If we substitute 1 mole in equation (2) with 55.845 g, it becomes:

55.845 g of Fe contains = 6.022\times 10^{23} atoms

Reversing the equation yields

6.022\times 10^{23} atoms of Fe correspond to 55.845 g

1 atom of Fe corresponds to \frac{55.845}{6.022\times 10^{23}} g

3.51\times 10^{23} one atom corresponds to

\frac{55.845}{6.022\times 10^{23}}\times 3.51\times 10^{23}

On computation,

3.51\times 10^{23} one atom corresponds to 32.55 g of Fe

Mass of Fe = 32.55 g

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