The intensity of the sound increases because sound waves are mechanical waves, meaning they cannot move through a vacuum and require a medium to propagate.
Answer:
2.5 m
Explanation:
Billboard worker's weight = 800 N
Number of ropes = 2
Length of scaffold = 4 m
Weight of scaffold = 500 N
Tension present in rope = 550 N
The total torques will be

The worker is positioned at 2.5 m
Answer:

Explanation:
Let the charge on the large droplet be denoted as Q.
When the radius of the droplet is R, the electric potential for the larger droplet can be expressed as:

If it splits into n identical droplets, let the charge of each be "q" and their radius be "r".
Applying volume conservation gives us:


Now, the potential for the smaller droplets is given as:




Answer:
F = 0.535 N
Explanation:
We will apply energy concepts, considering both the peak and the bottom of the path.
Top
Em₀ = U = mg y
Bottom
= K = ½ m v²
Emo =
mg y = ½ m v²
v = √ (2gy)
y = L - L cos θ
v = √ (2g L (1 - cos θ))
Next, we will employ Newton's second law at the lowest point where the acceleration is centripetal.
F = ma
a = v² / r
For the turning radius, the cable length is r = L.
F = m 2g (1 - cos θ)
Now, let's find the result.
F = 2 1.25 9.8 (1 - cos 12)
F = 0.535 N