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777dan777
3 months ago
5

A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N. While it is being thrown, what is the a

cceleration experienced by the cheeseburger? Answer in units of m/s2
Physics
1 answer:
serg [3.5K]3 months ago
4 0
Clearly, someone would likely be terminated for throwing food.
You might be interested in
An ideal gas is allowed to expand isothermally from 2.00 l at 5.00 atm in two steps:
Sav [3153]

Heat supplied to the gas = Q = 743 Joules

Work applied to the gas = W = -743 Joules

\texttt{ }

Additional explanation

The Ideal Gas Law that should be remembered is:

\large {\boxed {PV = nRT} }

P = Pressure (Pa)

V = Volume (m³)

n = number of moles (moles)

R = Gas Constant (8.314 J/mol K)

T = Absolute Temperature (K)

Now, let’s proceed with the problem!

\texttt{ }

Given:

Initial volume of the gas = V₁ = 2.00 L

Initial pressure of the gas = P₁ = 5.00 atm

Unknown:

Work done on the gas = W =?

Heat supplied to the gas = Q =?

Solution:

Step A:

An ideal gas expands isothermally:

P_1V_1 = P_2V_2

5.00 \times 2.00 = 3.00 \times V_2

V_2 = 10 \div 3

V_2 = 3\frac{1}{3} \texttt{ L}

\texttt{ }

Next, we will determine the work performed on the gas:

W_A = -P_2(V_2 - V_1)

W_A = -3.00(3\frac{1}{3} - 2.00)

W_A = \boxed{-4 \texttt{ L.atm}}

\texttt{ }

Step B:

By utilizing the methodology mentioned earlier:

P_2V_2 = P_3V_3

3.00 \times 3\frac{1}{3} = 2.00 \times V_3

V_3 = 10 \div 2

V_3 = 5 \texttt{ L}

\texttt{ }

Next, we will ascertain the work completed on the gas:

W_B = -P_3(V_3 - V_2)

W_B = -2.00(5 - 3\frac{1}{3})

W_B = \boxed{-3\frac{1}{3} \texttt{ L.atm}}

\texttt{ }

Ultimately, we can calculate the total work done and heat supplied as follows:

W = W_A + W_B

W = -4 + (-3\frac{1}{3})

W = -7\frac{1}{3} \texttt{ L.atm}

W = -7\frac{1}{3} \times 101.33 \texttt{ J}

\boxed{W \approx -743 \textt{ J}}

\texttt{ }

\Delta U = Q + W

0 = Q + (-743)

\boxed{Q = 743 \texttt{ J}}

\texttt{ }

Learn more

  • Minimum Coefficient of Static Friction:
  • The Pressure In A Sealed Plastic Container:
  • Effect of Earth’s Gravity on Objects:

\texttt{ }

Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

5 0
3 months ago
A wire has an electric field of 6.2 V/m and carries a current density of 2.4 x 108 A/m2. What is its resistivity
Softa [3030]

Response:

The resistivity can be expressed as \rho = 2.5 *10^{-8} \ \Omega \cdot m

Clarification:

According to the information provided,

    The value of the electric field measures  E = 6.2 V/m

     The density of current is given as  J = 2.4 *10^{8} \ A/m^2

Typically, resistivity is represented in mathematical terms as

         \rho = \frac{E}{J}

by inserting values

        \rho = \frac{6.2}{2.4 *10^{8}}

        \rho = 2.5 *10^{-8} \ \Omega \cdot m

5 0
2 months ago
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