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BabaBlast
17 days ago
12

A=9y+3yx solve for y

Mathematics
2 answers:
lawyer [4K]17 days ago
8 0

Answer:

y=\frac{a}{(9+3x)}

Detailed explanation:

We start with

a=9y+3yx

Now solve the equation for y

This means we need to isolate y on one side

Step 1

Extract y as a common factor on the right side

a=y(9+3x)

Step 2

Divide both sides of the equation by (9+3x)

a/(9+3x)=y(9+3x)/(9+3x)

Step 3

Carry out the simplification

y=\frac{a}{(9+3x)}



Inessa [3.9K]17 days ago
3 0
The solution for y is y = \frac{a}{3(3 + x)}
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zzz [4035]

Answer:

Lines a and b are considered parallel due to their corresponding angles being equal.

Step-by-step explanation:

The corresponding angle postulate states that two lines are parallel when a transversal intersects them and their corresponding angles are congruent.

In this case, line a and line b are intersected by transversal e, with both corresponding angles measuring 110 (which are congruent), hence, according to the corresponding angle postulate, we can conclude that line a and line b are indeed parallel to each other.

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(HELP NEEDED ASAP!!!)The sequence below represents Marisa’s fine at the library for each day that she has an overdue book: $0.50
Svet_ta [4341]

Answer:

F(n)= 0.50+0.15

Step-by-step explanation:

The starting point is 0.50. Additionally, when adding a fine of 0.15, you would consider 0.15 as well.

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A sphere has a radius of 16 in. Which statements about the sphere are true? Check all that apply.
lawyer [4039]

Answer:

  • The sphere has a 32 in. diameter. CORRECT: A sphere's diameter equals twice its radius; therefore, if the radius is 16, then the diameter is 32.
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14 days ago
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Two boats start their journey from the same point A and travel along directions AC and AD, as shown below: ABC is a right triang
Inessa [3926]

*Refer to the image attached below

Answer:

346.4 ft

Step-by-step Explanation:

The distance between the boats, CD = BD - BC

Using trigonometry, find the length of BD in triangle ∆ABD and also calculate the length of BC in triangle ABC.

Length of BD in triangle ABD:

Opposite side to <30° = 300 ft

Adjacent side = BD

tan(30) = \frac{300}{BD}

BD*tan(30) = 300

Divide both sides by tan(30)

\frac{BD*tan(30)}{tan(30)} = \frac{300}{tan(30)}

BD = 519.6 ft (rounded to nearest tenth)

Length of BC in triangle ABC:

Opposite side to <60° = 300 ft

Adjacent side = BC

tan(60) = \frac{300}{BC}

BC*tan(60) = 300

Divide both sides by tan(60)

\frac{BC*tan(60)}{tan(60)} = \frac{300}{tan(60)}

BC = 173.2 ft (rounded to nearest tenth)

The distance, CD, between the boats is calculated as BD - BC

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5 days ago
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Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
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Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

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∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that  ΔBCD ~ ΔBSR, we obtain;

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1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).

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