Nuclear forces exists because the particles in the nucleus are ?

Answer:

In blood: Dispersed phase: blood cells; Dispersed medium: liquid plasma

In fruit jelly: Dispersed phase: fruit juice; Dispersed medium: pectin

Explanation:

The dispersed phase refers to the phase where colloidal particles are dispersed within another phase, known as the dispersion medium.

In blood, the tiny cells act as colloidal particles, forming the dispersed phase within the liquid medium identified as plasma.

Conversely, in fruit jelly, the fruit juice constitutes the dispersed phase while the solid pectin serves as the dispersed medium.

Response:

Here's my calculation

Clarification:

Assume the starting concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We need to determine the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's compile all the information in one location.

H₂ + I₂ ⇌ 2HI

I/mol·L⁻¹: 0.30 0.15 x

2. Calculate the concentration of HI

3. Plot the initial values

The graph below visualizes the initial concentrations as plotted on the vertical axis.

Answer:

She will likely notice an increase in tire pressure.

Explanation:

According to the ideal gas law, pressure is directly related to temperature. Therefore, as temperature rises, so does pressure:

PV = nRT (Where P denotes pressure, V is volume, n represents moles, R is the ideal gas constant, and T signifies temperature).

Temperature indicates the average kinetic energy among the gas molecules. Thus, when the temperature goes up, the kinetic energy increases accordingly, leading gas molecules to speed up and collide more frequently with each other and with the tire walls. These impacts are more forceful due to the increased speed.

Consequently, the pressure escalates because it results from the collisions of gas molecules against the tire’s walls.

Answer:

a. the temperature changes will be identical

Explanation:

Dissolving sodium hydroxide (NaOH) in water is an exothermic process, with the heat released calculated using:

Q = m×C×ΔT

Where Q indicates the heat released, m refers to the mass of the solution, C is the specific heat, and ΔH stands for temperature change.

The specific heat of both solutions remains the same (because both are the same solutions). Specific heat = C.

m denotes the mass of the solutions: 102g for experiment 1 and 204g for experiment 2.

The heat released, Q: If 2g releases X heat, then 4g releases 2X.

Thus, the temperature change for each experiment is:

Experiment 1:

X / 102C = ΔT

Experiment 2:

2X / 204C = ΔT

X / 102C = ΔT

Indicating that,

a. the temperature changes will be identical

Answer:

moles = 0.093 moles

Explanation:

Here, we analyze a reaction occurring in a vessel with a total pressure of 730 torr.

The total pressure can be expressed as:

Pt = Pwater + PO2

We need to ascertain the pressure of O2 since it will allow us to find the moles of KClO3 through stoichiometry.

The oxygen pressure is:

PO2 = 730 - 26 = 704 Torr

Next, we need to convert this pressure from Torr to Atm:

704 Torr divided by 760 Torr equals 0.9263 atm

Now, using the ideal gas equation:

PV = nRT

We can calculate the moles of O2, and consequently the moles of KClO3:

n = PV/RT

R equals 0.082 L atm /K mol

P equals 0.9263 atm

V equals 3.72 L

T equals 27 + 273 equals 300 K

Plugging in the values:

n = 0.9263 * 3.72 / 300 * 0.082

n = 0.14 moles

Finally, using stoichiometry, since 2 moles of KClO3 yield 3 moles of O2, we have:

moles of KClO3 = 0.14 * 2/3 = 0.093 moles of KClO3