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oksano4ka
12 days ago
6

How many grams of Fe are produced from 65.9 g of FeO given the following reaction: 3FeO + 2Al -> 3Fe +Al2O3

Chemistry
2 answers:
Alekssandra [2.7K]12 days ago
8 0

By applying the mole ratio alongside stoichiometry, one can calculate:

65.9 g FeO x (molar mass of FeO) x (3 mol Fe/ 3 mol FeO) x (molar mass of Fe).

Substitute the numbers in, and you're all set!

castortr0y [2.8K]12 days ago
4 0
Dividing 65.9 g of FeO by 72 (the molar mass of FeO), then dividing by 3, and subsequently multiplying by 3 and 56 results in =>
Approximately 54 grams
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The result is:

The new volume is: 2L

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Because the temperature remains constant, we can apply Boyle's Law to solve this issue.

Boyle's Law stipulates that:

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According to the information provided:

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Let's put the values into the equation:

2.5L*6.0atm=7.5atm*V_{2}

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