Answer:
3
/2
Step-by-step explanation:
Given that AC = BC, this is an isosceles triangle.
Since CD is perpendicular to AB, we find AD = DB = 0.5AB = 3/2
Now considering triangle ACD,[TAG_17]]
we will use Pythagoras' theorem,
AC =
AC = 3
/2
:-)
La ganancia de Brad fue del 30%
Explicación adicional:
La ganancia es el dinero obtenido al vender un producto por encima de su costo original.
La fórmula para calcular la ganancia es:

Datos:
Precio de compra del paquete de bebidas energéticas = £9.25
Precio de venta por botella = £1
Precio total por 12 botellas = 1 * 12 = £12
Ganancia = Precio de venta - Precio de compra
= 12 - 9.25
= £2.75
Así, la ganancia de Brad fue de £2.75
Luego,
Porcentaje de ganancia = (Ganancia / Precio de compra) * 100
= (2.75 / 9.25) * 100
= 0.30 * 100
= 30%
La ganancia de Brad fue del 30%
Palabras clave: Ganancia, pérdida
Aprende más sobre ganancia y pérdida en:
#AprendeConBrainly
Answer:
Step-by-step explanation:
There are 15 antennas in total.
Out of these, 3 are defective.
This means that 12 antennas are functioning: 15-3=12.
To ensure that no two defective antennas are adjacent, we need to have only one defective at a time placed between the functional ones.
So,
We align the 13 functional antennas, then look for the spaces where the defective antennas can fit
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each gap represented by an underscore indicates a possible location for a defective antenna, allowing for just one per space.
Consequently, there are 14 potential spots for the defective antennas. With 3 defectives, we are dealing with a combinatorial arrangement.
ⁿCr= n!/(n-r)!r!
The total number of arrangements possible is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
That gives us 364 distinct ways to arrange them.
In certain cases, a function necessitates multiple formulas to achieve the desired outcome. An example is the absolute value function \displaystyle f\left(x\right)=|x|f(x)=∣x∣. This function applies to all real numbers and yields results that are non-negative, defining absolute value as the magnitude or modulus of a real number regardless of its sign. It indicates the distance from zero on the number line, requiring all outputs to be zero or greater.
<pwhen inputting="" a="" non-negative="" value="" the="" output="" remains="" unchanged:="">
\displaystyle f\left(x\right)=x\text{ if }x\ge 0f(x)=x if x≥0
<pwhen inputting="" a="" negative="" value="" the="" output="" is="" inverse:="">
\displaystyle f\left(x\right)=-x\text{ if }x<0f(x)=−x if x<0
Due to the need for two distinct operations, the absolute value function qualifies as a piecewise function: a function defined by several formulas for different sections of its domain.
Piecewise functions help describe scenarios where rules or relationships alter as the input crosses specific "boundaries." Business contexts often demonstrate this, such as when the cost per unit of an item decreases past a certain order quantity. The concept of tax brackets also illustrates piecewise functions. For instance, in a basic tax system where earnings up to $10,000 face a 10% tax, additional income incurs a 20% tax rate. Thus, the total tax on an income S would be 0.1S when \displaystyle {S}\leS≤ $10,000 and 1000 + 0.2 (S – $10,000) when S > $10,000.
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