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elena-14-01-66
9 days ago
14

What accounts for the two precipitation peaks in mbandaka?

Physics
1 answer:
serg [3.2K]9 days ago
7 0

The dual peaks of precipitation in Mbandaka, occurring from March to April and September to November, arise from the intertropical convergence zone.

The intertropical convergence zone is a slender belt found close to the equator. It is where the air masses from the northern and southern hemispheres converge, leading to decreased atmospheric pressure. Due to the interaction of these air masses within the intertropical convergence zone, lower air pressure often results in cooler air or increased rainfall, particularly in Mbandaka during the periods of March to April and, most notably, from September to November.

<span>Given that Mbandaka is situated at the center of the Tumba-Ngiri-Maindombe region, recognized as a Wetland of International Importance, there’s a significant likelihood for the area to receive over 60mm of rainfall annually, with temperatures ranging between 23 and 26 degrees Celsius.</span>

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10 days ago
Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of t
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Answer:

1/7 kg

Explanation:

Refer to the attached diagram for enhanced clarity regarding the question.

One of the blocks weighs 1.0 kg and accelerates downward at 3/4g.

g denotes the acceleration due to gravity.

Let M represent the block with known mass, while 'm' signifies the mass of the other block and 'a' refers to the acceleration of body M.

Given M = 1.0 kg and a = 3/4g.

By applying Newton's second law; \sum fy = ma_y

For the body with mass m;

T - mg = ma... (1)

For the body with mass M;

Mg - T = Ma... (2)

Combining equations 1 and 2 gives;

+Mg -mg = ma + Ma

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Substituting M = 1.0 kg and a = 3/4g into this equation leads to;

3/4 g-g = -m(3/4 g+g)

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3 0
1 month ago
Compare the time period of two simple pendulums of length 4m and 16m at a place.
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Answer:

The period of the pendulum measuring 16 m is double that of the 4 m pendulum.

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T=2\,\pi\,\sqrt{ \frac{L}{g} }

where "g" denotes the local gravitational acceleration.

Since both pendulums are positioned at the same location, the value of "g" will be consistent for both, and when we compare the periods, we find:

T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2

Thus, the duration of the 16 m pendulum is two times that of the 4 m one.

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Response:

Q = 8,345 * v

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