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DENIUS
1 day ago
5

In how many ways can you receive four cards of the same face value and one card from the other 48 available cards?

Mathematics
1 answer:
Zina [9.1K]1 day ago
5 0
A deck contains 13 groups of 4 cards, indicating 13 unique ways to select four cards sharing the same face value. Any subsequent card drawn will necessarily represent a different face value. Consequently, the total combinations for selecting 5 cards—4 of which share the same face value and 1 diverging—amount to 13 x 48.

13 x 48 = 624.


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Two models of a product - Regular (X) and Deluxe (Y) - are produced by a company. A linear programming model is used to determin
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The correct answer is C. 100
3 0
10 days ago
Disney held a breakfast for parents and their children to eat with Mickey and Minnie Mouse (and the rest of the gang, too!) Adul
Svet_ta [9500]
I trust this information is useful to you.



Let a represent the number of adults.



Then, the number of children will be 500-a.



From here, we set up the equation: 17.95×a + 12.95×(500-a) = 7355.



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3 0
1 month ago
Point T is the midpoint of RS, W is the midpoint of RT, and Z is the midpoint of WS. If the length of TZ is x, find the lengths
PIT_PIT [9117]

Let RS be denoted as y.

Given that T is the midpoint of RS, this results in RT = TS = \frac{y}{2}

And W acting as the midpoint of RT, leads to

thus RW = WT = \frac{\frac{y}{2} }{2} = \frac{y}{4}

Given that Z is the midpoint of WS.

Meaning WZ = ZS = \frac{WS}{2} = \frac{WT+TS}{2} = \frac{(\frac{y}{4} +\frac{y}{2} )}{2} =\frac{3y}{8}

Consequently, TZ = TS - ZS = \frac{y}{2} -\frac{3y}{8} = \frac{4y-3y}{8} = \frac{y}{8}

However, TZ is defined as x.

Thus, \frac{y}{8} = x

y = 8x = RS.

A) Length of RW = \frac{y}{4} = \frac{8x}{4} = 2x

B) Length of WZ = \frac{3y}{8} =\frac{3*8x}{8} = 3x

C) Length of RS = y = 8x

D) Length of ZS = WZ = 3x.

An image is provided for clarification.

8 0
4 days ago
Two boats start their journey from the same point A and travel along directions AC and AD, as shown below: ABC is a right triang
Inessa [9000]

*Refer to the image attached below

Answer:

346.4 ft

Step-by-step Explanation:

The distance between the boats, CD = BD - BC

Using trigonometry, find the length of BD in triangle ∆ABD and also calculate the length of BC in triangle ABC.

Length of BD in triangle ABD:

Opposite side to <30° = 300 ft

Adjacent side = BD

tan(30) = \frac{300}{BD}

BD*tan(30) = 300

Divide both sides by tan(30)

\frac{BD*tan(30)}{tan(30)} = \frac{300}{tan(30)}

BD = 519.6 ft (rounded to nearest tenth)

Length of BC in triangle ABC:

Opposite side to <60° = 300 ft

Adjacent side = BC

tan(60) = \frac{300}{BC}

BC*tan(60) = 300

Divide both sides by tan(60)

\frac{BC*tan(60)}{tan(60)} = \frac{300}{tan(60)}

BC = 173.2 ft (rounded to nearest tenth)

The distance, CD, between the boats is calculated as BD - BC

= 519.6 - 173.2 = 346.4 ft

4 0
27 days ago
Read 2 more answers
Carmen is planning rail lines for a new train station. Help her find m1. Explain how you found  that solution.
tester [8842]
I have included a screenshot of the entire question along with its accompanying diagram.

Answer:
∠1 = 163°

Explanation:
1- finding angle 2:
Given that ∠2 together with 17° creates a straight angle, their total is 180°.
Thus:
180 = 17 + ∠2
Solving for ∠2 gives us:
∠2 = 180 - 17
∠2 = 163°

2- finding angle 1:
Since lines a and b are parallel, ∠1 and ∠2 are alternate angles and therefore equal.
We determined that ∠2 = 163°, leading to:
∠1 = 163°

I hope this clarifies things!:)

3 0
27 days ago
Read 2 more answers
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