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Klio2033
3 months ago
8

The Big River Casino is advertising a new digital lottery-style game called Instant Lotto. The player can win the following mone

tary prizes with the associated probabilities: 5% probability to win $10 4% probability to win $15 3% probability to win $30 1% probability to win $50 0.1% probability to win the Grand Prize, $1000. (a) Calculate the expected value of the prize for one play of Instant Lotto. (b) As a promotion, a visitor to the casino is given 20 free plays of Instant Lotto. What is the probability that the visitor wins some prize at least twice in the 20 free plays? (c) The number of people who play Instant Lotto each day is approximately normally distributed with a mean of 800 people and a standard deviation of 310 people. What is the probability that a randomly selected day has at least 1000 people play Instant Lotto?
Mathematics
1 answer:
Inessa [12.5K]3 months ago
5 0

Answer:

(a) For a single play of Instant Lotto, the anticipated value of the prize amounts to $3.50.

(b) The likelihood that a visitor secures a prize at least two times during the 20 free plays is 0.2641.

(c) The chance of a randomly chosen day having 1000 or more players of Instant Lotto is 0.2579.

Step-by-step explanation:

(a)

The probability distribution for the monetary awards in Instant Lotto is defined as follows:

X P (X = x)

$10    0.05

$15    0.04

$30    0.03

$50    0.01

$1000  0.001

$0      0.869

___________

Total =   1.000

The expected value for one Instant Lotto play can be computed as follows:

E(X)=\sum x\cdot P (X=x)

         =(10\times 0.05)+(15\times 0.04)+(30\times 0.03) \\+ (50\times 0.01)+(1000\times 0.001)+(0\times 0.869)\\=0.5+0.6+0.9+0.5+1+0\\=3.5          

Consequently, the expected prize value for a single Instant Lotto play is $3.50.

(b)

Define X as the count of prizes a visitor wins.

A visitor receives n = 20 complimentary plays of Instant Lotto.

The probability of winning in any of the 20 games is p = 1/20 = 0.05.

The outcomes in the 20 plays are independent of one another.

The variable X adheres to a Binomial distribution characterized by parameters n = 20 and p = 0.05.

To find the probability that the visitor wins a prize at least twice in these 20 plays, perform the following calculation:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-[{20\choose 0}0.05^{0}(1-0.05)^{20-0}]-[{20\choose 1}0.05^{1}(1-0.05)^{20-1}]\\=1-0.3585-0.3774\\=0.2641

The resulting probability that the visitor wins a prize at least twice during the 20 plays is 0.2641.

(c)

Let X denote the number of individuals playing Instant Lotto each day.

The variable X is assumed to be normally distributed with a mean value of μ = 800 players and a standard deviation of σ = 310 players.

To ascertain the probability that on a random day, at least 1000 people participate in Instant Lotto, consider the following:

Implementing continuity correction:

P (X ≥ 1000) = P (X > 1000 + 0.50)

                    = P (X > 1000.50)

                    =P(\frac{X-\mu}{\sigma}>\frac{1000.50-800}{310})

                    =P(Z>0.65)\\=1-P(Z

The probability of having at least 1000 players on any random day is 0.2579.

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