Assume there are 365 days in a year.
1 answer:
Response:
1) The likelihood that ten students in a classroom have distinct birthdays is 0.883.
2) The likelihood that at least two out of ten students share a birthday is 0.002.
Detailed explanation:
Given: Assuming 365 days are in a year.
To find: 1) What is the probability that ten students in a classroom have unique birthdays?
2) What is the probability that at least two among ten students have a birthday in common?
Solution:
Total outcomes = 365
1) The chance that ten students in a class hold different birthdays is
The first student can have their birthday on any of the 365 days, the second can only on 364/365 and so forth...
The chance that ten students in a class have distinct birthdays is 0.883.
2) The likelihood that at least two out of ten students share a birthday
P(2 on the same day) = 1 - P(2 not on the same day)
The probability that at least two students in a class have the same birthday is 0.002.
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Answer:
Upon solving for y, we find:
By substitution, we have:
Thus, we arrive at:
And for x, we determine:
This gives us a length of 76 and a width of 12.5.
Step-by-step explanation:
We are dealing with a rectangle. The formula for the perimeter is:
Here, x denotes the length and y the width. The following conditions can be established:
Substituting these values yields:
When we solve for y, we find:
By substitution, we obtain:
Thus, we conclude:
The length is found to be 76, while the width measures 12.5.