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Strike441
29 days ago
6

Gregor Mendel finished his pea plant experiments in 1863 and published his results in 1866. However, few scientists saw Mendel's

paper for three decades. Even after all that time, Mendel's discoveries revolutionized the field of genetics. What did Mendel discover about the principles of heredity? Choose the two statements that apply. Select 2 correct answer(s) Question options: A Individuals get one factor for a trait from each parent. B Genetic material is genes on DNA. C A dominant factor can hide the expression of a recessive factor when both are present. D Mothers contribute factors for some traits while fathers contribute factors for others. if you do not know do not answer or you will be reported selet two answer
Physics
1 answer:
serg [3.5K]29 days ago
8 0
Individuals inherit one factor per trait from each parent, and a dominant factor can conceal the expression of a recessive one when both are present.
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No official standard exists for extinguisher-cylinder colors. that said, a red cylinder is typically associated with which type
kicyunya [3294]
Fire extinguishers are commonly colored red, which aligns with the red of fire trucks and the general association of red with emergencies. Although there is no official standard, altering the colors could lead to confusion, potentially endangering lives. Therefore, it seems that red will likely remain the color of fire extinguishers for the foreseeable future.
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8 0
1 month ago
Water, of density 1000 kg/m3, is flowing in a drainage channel of rectangular cross-section. The width of the channel is 15 m, t
ValentinkaMS [3465]

Answer:

The flow rate of water is (300000kg/s) = (300000l/s)

Explanation:

To compute the volume of moving fluid per second in the channel, we consider the channel's section, the water depth, and the fluid velocity:

Volume flow rate = 15m × 8m × (2.5m/s) = 300 m³/s

To find the mass or liters of water flowing per second, multiply the volume of circulating fluid by the water's density:

Flow rate of water = (300m³/s) × (1000kg/m³) = (300000kg/s) = (300000l/s)

It is important to note that 1kg of water is approximately equivalent to 1 liter.

8 0
1 month ago
A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 245 Hz. A person on the pl
Keith_Richards [3271]
through the Doppler effect. The formula for apparent frequency is derived as F apparent = F real x (Vair ± Vobserver) / (Vair ± Vsource). In this scenario, should the observer move towards the source—place a positive sign in the numerator and a negative in the denominator. Since the observer approaches the wall, we apply the formula to derive the necessary speed.
4 0
1 month ago
Newton’s law of cooling states that dx dt = −k(x−A) where x is the temperature,t is time, A is the ambient temperature, and k &g
Maru [3345]

Answer:

a) X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}

b) D does not influence the long-term results.

Explanation:

Given that

\dfrac{dx}{dt}=-k(x-A)

A = A0 cos(ωt)

\dfrac{dx}{dt}=-k(x-A_o cos(\omega t))

\dfrac{dx}{dt}+kx=kA_o cos(\omega t)This is a linear equation hence the integration factor, I

I=e^{\int kdt}

I=e^{kt}Now using the characteristics of linear equations

e^{kt} X=\int e^{kt} kA_o cos(\omega t) dt +C

e^{kt} X= kA_o \dfrac{e^{kt}}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+C

b) At t= 0

X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}

Thus, the initial condition

does not affect the long-term outcome.

X(0)=\dfrac{k^2A_o}{\omega^2+k^2}+C

5 0
1 month ago
A hard rubber rod with an electric potential energy of 5.2 × 10–3 J has a charge of 4.0 µC at the tip. What is the electric pote
Keith_Richards [3271]
1) The electric potential energy can be defined as the product of the electric potential and the associated charge:
U=q V
where
q refers to the charge
V denotes the electric potential

In this scenario, the charge on the rod is q=4.0 \mu C = 4.0 \cdot 10^{-6}C, and the potential energy is U=5.2 \cdot 10^{-3} J, thus we may rearrange the earlier formula to find the electric potential at the tip:
V= \frac{U}{q}= \frac{5.2 \cdot 10^{-3}J}{4.0 \cdot 10^{-6} C}=1300 V=1.3 \cdot 10^3 V

2) Using this same formula, if the charge changes to q=2.0 \mu C = 2.0 \cdot 10^{-6} C, the resulting electric potential will be:
V= \frac{U}{q}= \frac{5.2 \cdot 10^{-3} J}{2.0 \cdot 10^{-6}C}=2600 V = 2.6 \cdot 10^{3}V
8 0
1 month ago
Read 2 more answers
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