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1 month ago

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Barker is unloading 20kg bottles of water from this delivery truck when one of the bottles tips over and slides down the truck r

amp that is inclined at an angle of 30 degrees to the ground. what amount of force moves the bottle down the ramp?

1 answer:

Maru [3.3K]1 month ago

8 0

<span>The primary force acting on the bottle is gravity. Since the incline is at 30 degrees, the full force of gravity does not apply as the ramp prevents the bottle from descending straight down. By calculating the sine of 30 degrees, it can be determined that the gravitational force acting on the bottle is 4.9 meters per second, and with the 20 kg weight of the bottle, the force acting on it is 98 Newtons.</span>

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A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m

serg [3582]

Response:

The man's speed is 0.144 m/s

Explanation:

This exemplifies conservation of momentum.

The momentum of the ball prior to being caught must equal the momentum of the man-ball system after catching the ball.

Mass of the ball = 0.65 kg

Mass of the man = 54 kg

Speed of the ball = 12.1 m/s

The momentum of the ball before impact can be calculated as mass multiplied by velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After catching the ball, the momentum of the combined system is

(0.65 + 54)Vf = 54.65Vf

Where Vf denotes their final shared velocity.

Setting the initial momentum equal to the final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

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1 month ago

As a rough approximation, the human body may be considered to be a cylinder of length L=2.0m and circumference C=0.8m. (To simpl

inna [3103]

Thermal Power is approximately 460W. According to the Stephan-Boltzmann Law Formula: P = єσT⁴A, where: P = radiation energy, σ = Stefan-Boltzmann Constant, T = absolute temperature in Kelvin, є = emissivity of the material, and A = the surface area. Given that σ = 5.67 x 10^(-8), ε = 0.6, and T = 30°C which converts to Kelvin as 303K, with the human body dimensions of 2m length and 0.8m circumference leading to an area of 1.6m², so thermal power equals 0.6 x 5.67 x 10^(-8) x 303⁴ x 1.6 = 458.8W. Rounding gives about 460W.

4 0

1 month ago

Jeff's body contains about 5.46 L of blood that has a density of 1060 kg/m3. Approximately 45.0% (by mass) of the blood is cells

ValentinkaMS [3465]

Answer:

a) Blood mass is $m= 5.7876kg$

b) The count of blood cells is $N_t=1.04*10^{13}$

Explanation:

From the problem statement, we learn that

The blood volume is $V_b = 5.46 \ L = \frac{5.46}{1000} = 0.00546m^3$

The density of blood is $\rho_b = 1060 kg/m^3$

% of blood which consists of cells is = 45.0%

the % of blood that is plasma is = 55.0%

density of blood cells is $\rho_d = 1125kg/m^3$

% of cells that are white is = 1%

% of cells that are red is = 99%

The red blood cell diameter is = $7.5 \mu m = 7.5*10^{-6}m$

The red blood cell radius is $= \frac{7.5*10^{-6}}{2} = 3.75*10^{-6}m$

The mass is generally represented mathematically as

$m = \rho_b * V_b$

Substituting values

$m = 1060 * 0.00546$

$m= 5.7876kg$

Cell mass is $m_c$ = 45% of m

= 0.45 * 5,7876

= 2.60442 kg

The volume of cells is $V_c$ = $\frac{m_c}{\rho_d}$

$= \frac{2.60442}{1125}$

$= 2.315 *10^{-3} m^3$

The white blood cells volume is $V_w$ = 1% of the cells volume

$= \frac{1}{100} * 2.315*10^{-3}$

$= 2.315*10^{-5}m^3$

The volume of a single cell is $V_s = 4 \pi r^3$

$= 4*(3.142) * (3.75*10^{-6})^3$

$= 2.21*10^{-16}m^3$

The red blood cells volume is $V_r = V_c - V_w$

$=2.315*10^{-3} - 2.315*10^{-5}$

$= 2.29*10^{-3}m^3$

The total red blood cell count is $= \frac{V_r}{V_s}$

$= \frac{2.29 *10^{-3}}{2.21*10^{-16}}$

$= 1.037*10^{13}$

The total white blood cell count is $=\frac{V_w}{V_s}$

$= \frac{2.315 * 10^{-5}}{2.21*10^{-16}}$

$= 1.04*10^{11}$

The overall number of blood cells is $N_t= 1.037*10^{13} + 1.04*10^{11}$

$N_t=1.04*10^{13}$

6 0

1 month ago

Read 2 more answers

On a caterpillars map all distances are marked in kilometers . The caterpillars map shows the distance between two milkweed plan

ValentinkaMS [3465]

Answer:

The equivalent distance in kilometers is 4012 × $10^{-6}$ km.

Explanation:

It's known that 1 millimeter converts to $10^{-3}$ meters. Then, 1 meter converts to $10^{-3}$ kilometers. Therefore, the conversion for 1 millimeter to kilometers can be stated as

1 mm = $10^{-3}$ m

1 m = $10^{-3}$ km

Thus, 1 mm = $10^{-3}$ × $10^{-3}$ km = $10^{-6}$ km.

Given the distance of 4012 mm, the corresponding distance in kilometers will be

4012 mm = 4012 × $10^{-6}$ km.

The distance therefore is 4012 × $10^{-6}$ km.

5 0

2 months ago

In what processes do proteins in the electron transport chain participate?

kicyunya [3294]

Answer:

1. Reactions involving oxidation and reduction along with proton pumping

2. Reactions involving phosphorylation and proton pumping

Explanation:

During oxidative phosphorylation, there is a transfer of electrons from donors to acceptors, which constitutes a redox reaction.

These redox reactions liberate energy that is utilized to produce ATP. In eukaryotic cells, these reactions are performed by protein complexes found in the mitochondria, while in prokaryotic cells, the proteins are positioned in the intermembrane space of the cells. These interconnected protein complexes are referred to as electron transport chains.

8 0

1 month ago