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Lena
2 months ago
15

NASA is sending a probe to Alpha Centauri and then to Sirius. A problem with the probe is noticed while it is at Alpha Centauri,

so it must go back to Erth before going to Sirius. Alpha Centauri is 4.3 light-years away from Earth and Sirius is 8.6 light-years away. The probe is traveling at 18.03 km/s, there are 1.58125 x 10-5 light-years in one astronomical unit. How long will the probe have been traveling from when it first leaves Earth to when it arrives at Sirius?
Mathematics
1 answer:
zzz [12.3K]2 months ago
7 0
Total time taken = 9.0252 *10^12 s. Step-by-step explanation: Data provided: - Distance from Earth to Alpha Centauri: 4.3 light years. - Distance from Earth to Sirius: 8.6 light years. - Probe speed: V = 18.03 km/s. - 1 AU equals 1.58125 x 10^-5 light-years. Objective: Determine the total time the probe has been in motion from leaving Earth to reaching Sirius. Solution: - Journey is tracked for each destination sequentially:                      Earth ------> Alpha Centauri: d_1 = 4.3 light years                      Alpha Centauri ------> Earth: d_2 =4.3 light years                      Earth ------> Sirius: d_3 = 8.6 light years                      Sum of distances = D = 17.2 light years. - Now, we convert the total distance into kilometers (SI units):                             1 AU  ----------> 1.58125 x 10^-5 light-years                             x AU  ----------> 17.2 light years. - By proportions:                              x = 17.2 / (1.58125 x 10^-5) = 1087747.036 AU. Also,                             1 AU  ---------------------> 149597870700 m                              1087747.036 AU  ----> D m. - Using proportions:                              D =  1087747.036*149597870700  = 1.62725*10^17 m. - Finally, applying the speed-distance-time formula:                               Time = Distance traveled (D) / V                               Time = 1.62725*10^17 / (18.03*10^3). Final answer: Time = 9.0252 *10^12 s.
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John averages 58 words per minute on a typing test with a standard deviation of 11 words per minute. Suppose John's words per mi
Zina [12379]

Answer:

When x = 72, the z score is:

z = \frac{72-58}{11}= 1.273

The average is 58

This z-score indicates that x= 72 is 1.273 standard deviations above the mean.

Step-by-step explanation:

Let’s consider the following details for this question: John's typing speed on a test is assumed to follow a normal distribution. Let X denote the number of words he can type in a minute. Hence, X ~ N(58, 11). It’s important to round the result to three decimal points if needed.

Provide your response below for words per minute on a typing test conducted on Sunday. The z score when x = 72 is

In this scenario, we acknowledge that the variable under consideration is represented by a normal distribution:

X \sim N (\mu= 58, \sigma=11)

The formula for the z score is as follows:

z = \frac{X -\mu}{\sigma}

By substituting values, we derive:

z = \frac{72-58}{11}= 1.273

The mean is 58

This z-score indicates that x= 72 is 1.273 standard deviations higher than the mean.

8 0
1 month ago
Write an absolute value equation to satisfy the given solution set shown on a number line.
babunello [11817]
IX - 4I ≤ 4

Step-by-step explanation:

The number line indicates that the possible values of x fall within the range:

0 ≤ x ≤ 8

We aim to create an absolute value equation to encompass this set of potential solutions.

An example of such an equation is:

IX - 4I ≤ 4

To form this, we find the midpoint M of our set, which is 4 in this case.

Then, we write:

Ix - MI  ≤ IMI

It's important to note my use of the inclusive sign, as the filled dots indicate that the endpoints x = 0 and x = 8 are part of the solution, differing from empty dots which denote an open set requiring <  > signs.

8 0
23 days ago
Town Hall is located 4.3 miles directly east of the middle school. The fire station is located 1.7 miles directly north of Town
PIT_PIT [12445]

Answer:

2.1 miles

Step-by-step explanation:

Refer to the attached illustration (you need to include all the mentioned locations and the distances between them),

enabling us to create a right triangle between the school and the hospital with side measures of: 1.7 and 1.2 miles

and the green line represents the direct path from the school to the hospital; thus, applying the Pythagorean theorem will yield the result:

\sqrt{1.7^2+1.2^2}\\=\sqrt{2.89+1.44}\\=\sqrt{4.33} \\ =2.081

When rounded to the nearest tenth:

2.1 miles

4 0
1 month ago
The length and width of a book cover are 22.2cm and 12 cm respectively
zzz [12365]

The dimensions of the book cover are 28.3 centimeters in length and 21 centimeters in width. Calculate the range of values for both the actual length and width of the book cover. Minimum length = (28.3 - 0.05) cm and maximum length = (28.3 + 0.05) cm, thus 28.25 cm ≤ length < 28.35 cm.

Hope this information is helpful!

8 0
1 month ago
Triangle MRN is created when an equilateral triangle is folded in half. Triangle N R M is shown. Angle N R M is a right angle. A
Inessa [12570]

Answer:

El valor de x es 4.

Explicación paso a paso:

Se indica que el triángulo MRN surge al doblar un triángulo equilátero por la mitad.

Esto sugiere que el triángulo equilátero original es MNO y que NR actúa como bisectriz perpendicular (una línea que divide un segmento en dos partes iguales formando un ángulo recto).

La longitud del lado del triángulo es

NO = NS + SM = 6 + 2 = 8

Dado que un triángulo equilátero tiene todos sus lados iguales y NR es la bisectriz perpendicular, se tiene que

RM = MO/2 = 8/2 = 4

El valor de x es 4.

7 0
1 month ago
Read 2 more answers
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