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Lena
13 days ago
15

NASA is sending a probe to Alpha Centauri and then to Sirius. A problem with the probe is noticed while it is at Alpha Centauri,

so it must go back to Erth before going to Sirius. Alpha Centauri is 4.3 light-years away from Earth and Sirius is 8.6 light-years away. The probe is traveling at 18.03 km/s, there are 1.58125 x 10-5 light-years in one astronomical unit. How long will the probe have been traveling from when it first leaves Earth to when it arrives at Sirius?
Mathematics
1 answer:
zzz [4K]13 days ago
7 0
Total time taken = 9.0252 *10^12 s. Step-by-step explanation: Data provided: - Distance from Earth to Alpha Centauri: 4.3 light years. - Distance from Earth to Sirius: 8.6 light years. - Probe speed: V = 18.03 km/s. - 1 AU equals 1.58125 x 10^-5 light-years. Objective: Determine the total time the probe has been in motion from leaving Earth to reaching Sirius. Solution: - Journey is tracked for each destination sequentially:                      Earth ------> Alpha Centauri: d_1 = 4.3 light years                      Alpha Centauri ------> Earth: d_2 =4.3 light years                      Earth ------> Sirius: d_3 = 8.6 light years                      Sum of distances = D = 17.2 light years. - Now, we convert the total distance into kilometers (SI units):                             1 AU  ----------> 1.58125 x 10^-5 light-years                             x AU  ----------> 17.2 light years. - By proportions:                              x = 17.2 / (1.58125 x 10^-5) = 1087747.036 AU. Also,                             1 AU  ---------------------> 149597870700 m                              1087747.036 AU  ----> D m. - Using proportions:                              D =  1087747.036*149597870700  = 1.62725*10^17 m. - Finally, applying the speed-distance-time formula:                               Time = Distance traveled (D) / V                               Time = 1.62725*10^17 / (18.03*10^3). Final answer: Time = 9.0252 *10^12 s.
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