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puteri
8 days ago
12

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

Co3+]= 0.190 M , [Co2+]= 0.205 M , and [Cl−]= 0.144 M , and the pressure of Cl2 is PCl2= 7.30 atm ?
Chemistry
1 answer:
VMariaS [2.6K]8 days ago
6 0

Response:

Ecel =0,04 V

Clarification:

Utilize the Nernst equation,

Ecel= Ecelº - (RT/nF)*lnQ

where R=8,314 J/molK, T=25ºC=298K and F =96 485 Coulombs/mol e- and n=number of moles of electrons exchanged in the balanced equation. Q represents the ratio of products to reactants raised to their respective stoichiometric coefficients; use partial pressures if a substance is a gas

Construct the redox half-equations and confirm the balance of electron count. In this scenario, no modifications are necessary

2Cl−(aq)→Cl2(g) + 2e-

2CO3+(aq) + 2e-→2CO2+(aq)

2Cl−(aq) + 2CO3+(aq) →2CO2+(aq) + Cl2(g)

Thus

Ecel= 0.483 V -  0.013Ln ([CO2+]^2*PCl2] / [CO3+]^2*[Cl-]^2)

Ecel= 0.483 V -  0.013Ln ([0.205]^2 * 7.3] / [0.19]^2*[0.144]^2)

Ecel =0,04 V

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4 0
1 month ago
When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq), 3.14 kJ of heat are produced. Determine the enthalpy change per mole o
Alekssandra [2711]

Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.

Explanation:

First, we need to determine the moles of Zn and HCl.

\text{Moles of }Zn=\frac{\text{Mass of }Zn}{\text{Molar mass of }Zn}

The molar mass of Zn is 65 g/mole

\text{Moles of }Zn=\frac{1.34g}{65g/mole}=0.0206mole

and,

\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of solution}=0.750M\times 0.0600=0.0450mole

Next, we must identify the limiting reagent and the excess reagent.

The chemical reaction given is:

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

According to the balanced reaction we find that

1 mole of Zn reacts with 2 moles of HCl

Thus, 0.0206 moles of Zn react with 0.0206\times 2=0.0412 moles of HCl

This leads us to determine that HCl is the excess reagent because the moles provided exceed the required moles, while Zn is limiting and restricts product formation.

Now to find the enthalpy change for each mole of zinc reacting in this reaction.

From the reaction we gather that,[ [TAG_59]]

0.0206 moles of Zn yield heat = 3.14 kJ

This implies that 1 mole of Zn generates heat = \frac{3.14kJ}{0.0206mol}=152.4kJ/mol

Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.

5 0
16 days ago
Find the specific heat of sikver in J/g C if 38.5 cal is required to heat 25.0g of silver from 31.5 C to 58.7 C (1cal=4.184 J)
alisha [2704]

Answer:

The specific heat value for silver is 0.236 J/g-C.

Explanation:

Silver has a mass of 25 grams.

The temperature shifts from 31.5° C to 58.7° C.

The required heat is equivalent to 25 g.

To determine silver's specific heat, the following equation applies:

Q=mc\Delta T

Where c represents the specific heat of silver.

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{38.5 \times 4.184}{25(58.7-31.5)}\\\\c=0.236\ J/g-C

Thus, the specific heat of silver is 0.236 J/g-C.

7 0
28 days ago
"solid potassium iodide decomposes into iodine gas and solid potassium. Write a a balanced chemical equation for this reaction"
Alekssandra [2711]


Now, construct a balanced equation:

2KI (s) ----\ \textgreater \ 2K(s) + I_2 (g)

I_2 exists in its gaseous form as a diatomic molecule.
3 0
29 days ago
An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.
KiRa [2711]

Response:

0.8853 mL

Clarification:

Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:

  • 13 lb * \frac{0.454kg}{1lb} = 5.902 kg

Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:

  • 15 mg/kg * 5.902 kg = 88.53 mg

Finally, we compute the necessary mL of suspension, utilizing its concentration:

  • 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL
8 0
1 month ago
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