Response: The updated temperature stands at 10643 K
Clarification:
The combined gas law integrates Boyle's law, Charles's law, and Gay-Lussac's law.
The equation for this law is given by:
where,
= initial gas pressure = 750.0 mm Hg = 0.98 atm (760mmHg=1atm)
= final gas pressure = 3.50 atm
= initial gas volume = 2.00 L
= final gas volume = 20.0 L
= initial gas temperature = 
= final gas temperature =?
Now substituting all the stated values into the equation, we obtain:
Thus, the new temperature results in 10643 K
Answer:
CH4
Explanation:
The ideal behavior of gases generally depends on the strength of intermolecular forces between gas molecules and whether polar bonds are present.
In the case of CCl4, polar bonds exist along with the more electronegative chlorine atom, leading to stronger intermolecular forces at 400K, as opposed to CH4 which contains only non-polar bonds.
Thus, at 400K, CH4 behaves more like an ideal gas compared to CCl4.
Answer:
B
Explanation:
Flammable substances contain chemicals that react with flames, thus making it their chemical property, particularly when they encounter other materials that cause a reaction.
Answer:
During this process, energy is released as a bond is formed.
Explanation:
The elements present on the left side of the reaction equation are known as reactants, while those on the right are called the products.
In this case, N(g) and N(g) are the reactants, and N2(g) along with energy are the products.
Post-reaction, N(g) has vanished and has been replaced by N2(g). It confirms that a bond exists between the two N(g).
Moreover, energy has been released as part of the products (indicated on the right side)
The accurate statement is ''A bond is formed and energy is released''
To determine the mass of the lead piece, we use the following equation: Q(heat) = mC delta T, where Q equals 78.0 j, M is the mass we want to find, C is the specific heat capacity (0.130 j/g/C), and delta T shows the temperature difference, set at 9.0 c. Rearranging the formula to solve for M gives us M = Q / c delta T. By substituting in the values, we conclude that M = 78.0 j / (0.130 j/g/C * 9.0 C), calculating this gives us a mass of 66.7 g of lead.
