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LekaFEV
8 days ago
14

A sample of oxygen gas was found to effuse at a rate equal to two times that of an unknown gas. what is the molar mass (in g/mol

) of the unknown gas?
Chemistry
1 answer:
Anarel [2.7K]8 days ago
4 0
<span>128 g/mol Applying Graham's law of effusion, we can utilize the formula: r1/r2 = sqrt(m2/m1) where r1 = effusion rate of gas 1 r2 = effusion rate of gas 2 m1 = molar mass of gas 1 m2 = molar mass of gas 2 Given that the atomic weight of oxygen is 15.999, the molar mass of O2 = 2 * 15.999 = 31.998. We can now insert the known values into Graham's equation to find m2. r1/r2 = sqrt(m2/m1) 2/1 = sqrt(m2/31.998) 4/1 = m2/31.998 Thus, we find m2 to be 127.992. Rounding to three significant figures yields 128 g/mol</span>
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Calculation Steps

The total number of particles is determined through Avogadro's Principle constant.


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