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LekaFEV
1 month ago
14

A sample of oxygen gas was found to effuse at a rate equal to two times that of an unknown gas. what is the molar mass (in g/mol

) of the unknown gas?
Chemistry
1 answer:
Anarel [2.9K]1 month ago
4 0
<span>128 g/mol Applying Graham's law of effusion, we can utilize the formula: r1/r2 = sqrt(m2/m1) where r1 = effusion rate of gas 1 r2 = effusion rate of gas 2 m1 = molar mass of gas 1 m2 = molar mass of gas 2 Given that the atomic weight of oxygen is 15.999, the molar mass of O2 = 2 * 15.999 = 31.998. We can now insert the known values into Graham's equation to find m2. r1/r2 = sqrt(m2/m1) 2/1 = sqrt(m2/31.998) 4/1 = m2/31.998 Thus, we find m2 to be 127.992. Rounding to three significant figures yields 128 g/mol</span>
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Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding?
lorasvet [2795]

Result:

Ions interact with hydrogen that has a partially positive charge, facilitating the dissolution of salt in water. On the other hand, sugar is a molecular compound connected by covalent bonds. In a polar covalent bond, the sharing of electrons is uneven

Clarification:

5 0
1 month ago
What is the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water
Tems11 [2777]

Response:

The mass percentage of a solution comprising 7.6 grams of sucrose and 83.4 grams of water equals 8.351 %.

Details:

Provided data:

Sucrose mass = 7.6 grams

Water mass = 83.4 grams

In this scenario, sucrose acts as the solute, while water is the solvent.

The calculation for mass percent of a solution is done using the following formula:

Mass percent = (Mass of Solute/Mass of Solution)(100)

As sucrose is the solute, the mass equals 7.6 grams.

The total mass of the solution, which includes both sucrose and water, comes out to:

Total mass = 7.6 grams + 83.4 grams = 91 grams

Therefore, applying the values gives mass percent = (7.6/91)(100) = 8.351 %.

7 0
3 months ago
Copper(II) bromide is used as a wood preservative. What mass of CuBr2 is needed to prepare 750.0 mL of a 1.25 M solution?
lorasvet [2795]
Calculation yields 209.53. The molar concentration is calculated by moles divided by volume. Given the volume of 750 mL, which translates to 0.75 L, the moles of CuBr₂ can be determined as molar concentration multiplied by volume, resulting in 1.25 × 0.75 = 0.9375. Mole count is derived from the mass of CuBr₂ divided by its molecular mass. The molecular mass of CuBr₂ is computed as 63.5 + 80 × 2 = 223.5, where the mass of Cu is 63.5 and that of Br is 80. Consequently, the mass needed amounts to 223.5 × 0.9375 = 209.53 g.
8 0
2 months ago
Read 2 more answers
Several amino acids are intermediates of the urea cycle, having side ammonia groups that join with free carbon dioxide (CO2) and
Alekssandra [3086]

Response:

A. Arginine

Clarification:

The urea cycle consists of biochemical processes that convert ammonia into urea.

Steps of the urea cycle:

  • Carbamoyl phosphate reacts with ornithine transcarbamoylase to form citrulline through the release of a phosphate group along with ornithine.
  • In the presence of argininosuccinate synthetase, the amino group from aspartate and the carbonyl from citrulline combine to create argininosuccinate. This reaction requires ATP.
  • Subsequently, argininosuccinate is split by argininosuccinase to yield arginine and fumarate.
  • Then, arginine is broken down by arginase to produce urea and ornithine. Ornithine is recycled back to mitochondria, restarting the urea cycle.
7 0
2 months ago
A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20∘C. What is the concentration of this solutio
KiRa [2933]

Response:

Mole fraction: 0.0157.

Molality: 0.889m

Mass%: 16%

Clarification:

The measurement units are mole fraction, molality, and mass percentage.

Mole fraction is calculated using moles of glucose relative to the total moles present.

The glucose moles for 1L is:

0.944 moles.

The moles of water in 1L are:

1L × (1.0624kg/L) × (1000g / 1kg) × (1mol / 18.02g) = 59.0 moles of water

Mole fraction is given by: 0.944 moles / (59.0 mol + 0.944mol) = 0.0157

Molality is defined as moles of solute (0.944) per kilogram of solution (1.0624kg):0.944mol / 1.0624kg =

0.889m

For mass percentage, the total mass equals 1062.4g, and the mass of 0.944 moles of glucose is:

0.944mol×(180.156g/1mol) = 170g of glucose. Mass%:

170g / 1062.4g ×100 = 16%

I trust this information is useful!
6 0
1 month ago
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