Joule’s law is a linear relationship, that is, the more heat you provide, the greater the temperature change. However, in the pr
1 answer:
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Explanation:
The term 'collision' refers to the interaction between two objects. There are two distinct types of collisions: elastic and inelastic.
In this scenario, two identical carts are heading towards each other at the same speed, resulting in a collision. In an inelastic collision, the momentum is conserved before and after the incident, but kinetic energy is lost.
After the event, both objects combine and move together at a single velocity.
The graph representing a perfectly inelastic collision is attached, illustrating that both carts move together at the same speed afterward.
Answer:
The work done, W = 19.6 J
Explanation:
It’s provided that
The mass of the block, m = 5 kg
The velocity of the block, v = 10 m/s
The coefficient of kinetic friction between the block and rough surface is 0.2
Distance traveled by the block, d = 2 m
As the block traverses the rough section, it loses energy equal to the work done by the kinetic energy.
W = 19.6 J
Thus, the change in kinetic energy of the block moving through the rough section is 19.6 J. Consequently, this is the required answer.
Answer:
a) Ф = 0.016 N / C m, b) q_{int} = 0.14 10⁻¹² C
Explanation:
a) For this scenario, we rely on Gauss's law
Ф = E.ds = /ε₀
As the field points in the x direction, there is no flux through the cylinder walls.
Ф = E A
The area of a circle is
A = π r
Ф = E π r
Ф = (x- 3.6) r
Now, let's compute
Ф = (3.7 -3.6) 0.16
Ф = 0.016 N / C m
b) Using Gauss's law, we have
q_{int} = Ф ε₀
Where the flow is present on both sides, at the face corresponding to x = 0, the flow is zero
q_{int} = 0.016 8.85 10⁻¹²
q_{int} = 0.14 10⁻¹² C