A uniform electric field of 2 kNC-1 is in the x-direction. A point charge of 3 μC initially at rest at the origin is released. W
1 answer:
The force due to electricity on the charge is calculated by multiplying the charge by the intensity of the electric field:
in our scenario, where
and 
, resulting in the force of
Initially, the kinetic energy of the particle is at zero (as it remains stationary), which means its final kinetic energy is equal to the work performed by the electric force over a distance of x=4 m:
in our scenario, where
Initially, the kinetic energy of the particle is at zero (as it remains stationary), which means its final kinetic energy is equal to the work performed by the electric force over a distance of x=4 m:
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Solution:
/ Em₀ = 0.30
Explanation:
In this problem, we apply the connection between mechanical energy, kinetic energy, and gravitational potential energy.
K = ½ m v²
U = mgh
We assess the mechanical energy at two positions:
Initial. Lower
Em₀ = K = ½ m v²
At its highest point
= U = mg and
Now let's compute
Em₀ = ½ m 3.6²
Em₀ = m 6.48
= m 9.8 × 0.2
= m 1.96
Thus the energy lost is given by:
/ Em₀ = m 1.96 / m 6.48
/ Em₀ = 0.30
This means that 30% of the sun's energy is transformed into potential energy.
There are various conversion possibilities.
This energy changes into thermal energy affecting the spores and air, since it cannot be regained.
Answer:
(A) The tension's magnitude grows to four times the initial value, 4F.
Explanation:
When an object travels in a circular path, a centripetal force is exerted upon it. In this instance, the centripetal force acting on the stone can be represented by .
Here, m denotes the mass of the object
v is the velocity or speed of the object
r signifies the radius of the circular path
Importantly, the tension corresponds to the centripetal force.
Initially, the string completes one revolution each second, and subsequently, it accelerates to perform two revolutions in the same time frame. This signifies that the speed has increased twofold.
Applying our formula:F =
where F indicates the tension in the string
assuming the starting speed is v, after doubling it becomes 2v
Maintaining the circle's radius, we arrive at:
F=
From this equation, it's clear that the initial tension has quadrupled.
Consequently, the magnitude of the tension increases to four times its original value, 4F.