Thrust is quantified as a reaction force, in accordance with Newton's third law. When a system accelerates or expels mass in one direction, this resulting mass generates a force of equal strength but in the opposite direction on that system. This relationship can be expressed mathematically as:
Where:
v = velocity of the exhaust gases as perceived from the rocket.
= Change in mass over time
The provided data is as follows:
After substitution, we obtain:
Answer:
The flux across the cube's surface is .
Solution:
According to the details provided:
Cube edge length, a = 8.0 cm = .
Volume charge density, .
Now,
To find the electric flux:
where
= electric flux
= permittivity of vacuum.
The volume charge density for this scenario is described by:
Cube volume, .
Thus,
.
The total charge can be derived from equation (2):
.
.
Now, insert the value of 'q' into equation (1):
.
Answer:
Explanation:
a) La fuerza neta que actúa sobre la caja en la dirección vertical es:
Fnet=Fg−f−Fp *sin45 °
aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.
Fnet=ma
ma=Fg−f−Fp *sin45 °
a=
=0.24 m/s²
Vf =Vi +at
=0.48+0.24*2
Vf=2.98 m/s
b)
Fnet=Fg−f−Fp *sin45 °
=Fg−0.516Fp−Fp *sin45 °
=30-1.273Fp
Fnet=0 (Ya que la velocidad es constante)
Fp=30/1.273
=23.56 N