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Dominik
24 days ago
13

A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases

by 7.28 mmHg. Density of mercury is 13.6 g/cm3. By how much does the fluid level rise in the side of the manometer that is open to the atmosphere?What would your answer be if the manometer used mercury instead?
Physics
1 answer:
Keith_Richards [3.2K]24 days ago
5 0
The rise in fluid level is 0.11 m, and for mercury, it is 0.728 cm or 7.28 mm. \nTo solve this, here’s the information we have: \n- Density of oil: [density value] \n- Change in pressure in the tank: [pressure change] \n- Density of mercury: [density value] \nTo find the fluid level rise in the manometer: \n1 mmHg equals 133.332 Pa. \nBased on the variables: g is the acceleration due to gravity and h represents the height of the fluid level. \nh = 0.11 m. \nUsing mercury, we find: \nh = 0.00728 m, which is 7.28 mm.
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