Answer:

Explanation:
The four wires are arranged in series: this setup indicates that the same current passes through them, while the total voltage from the battery, V0, equals the combined voltages across each resistor:

Additionally, the total resistance for this series configuration is

Using Ohm's law, we can determine the voltage V2 across wire 2:
(1)
Here, I represents the entire current flowing through the circuit, which is calculated as:

By substituting into equation (1), we derive V2:

The light's wavelength absorbed during the transition is 459 nm. Energy difference between the 5-d and the 6-s sub-levels in gold is expressed as ΔE. Let the wavelength associated with the electron's transition from the 5-d to the 6-s state be λ. The relationship that describes the connection between energy and wavelength is defined as: E = hc/λ, where E stands for photon energy, h represents Planck's constant, c is the speed of light, and λ denotes the wavelength of the photon. Therefore, the absorption wavelength in this transition stands at 459 nm.
Answer:
The radius is 
Explanation:
The problem states that
The magnetic field is 
The electron kinetic energy is 
In general, for a collision to happen, the centripetal force on the electron in its orbit must equal the magnetic force acting on it
This can be mathematically expressed as
=> 
Where m denotes the electron’s mass, which has a value of
v signifies the escape velocity, mathematically represented as

Thus,

applying indices

substituting these values


Answer:
The electric field strength, E = 45.19 N/C
Explanation:
It is indicated that,
Surface charge density on the first surface, 
Surface charge density on the second surface, 
The electric field at a location between the two surfaces can be calculated as:



Consequently, E = 45.19 N/C
Therefore, the electric field's magnitude at a point between both surfaces is 45.19 N/C.