Answer:
407 steps
Explanation:
Based on the question,
P = mgh/t........... Equation 1
Where P stands for power, m is mass, g denotes gravity, h is height, and t represents time.
Rearranging the equation to solve for h, we have:
h = Pt/mg............. Equation 2
Providing values: P = 746 W, t = 1 minute = 60 seconds, m = 70 kg.
Given constant: g = 9.8 m/s²
By substituting into equation 2
h = 746(60)/(70×9.8)
h = 44760/686
h = 65.25 m
h = 6525 cm
Calculating number of steps: 6525/16
The resulting number of steps = 407 steps
<span>First, apply Newton's second law of motion: F = ma.
Force equals mass times acceleration.
This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time,
we have force = (mass * velocity) / time,
leading us to conclude that (mass * velocity) / time will equal momentum / time.
Hence, we derive the equation mass * velocity = momentum.
Momentum = mass * velocity.
For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s,
Momentum = 6300 * 0.11,
resulting in P = 693 kg (m/s).
For the dolphin, having a mass of 50 kg and moving at 10.4 m/s,
Momentum = 50 * 10.4,
yielding P = 520 kg (m/s).
Thus, the elephant has a greater momentum (P) due to its larger size.</span>
Explanation:
The term 'collision' refers to the interaction between two objects. There are two distinct types of collisions: elastic and inelastic.
In this scenario, two identical carts are heading towards each other at the same speed, resulting in a collision. In an inelastic collision, the momentum is conserved before and after the incident, but kinetic energy is lost.
After the event, both objects combine and move together at a single velocity.
The graph representing a perfectly inelastic collision is attached, illustrating that both carts move together at the same speed afterward.
Answer:
The overall length of the spiral, designated as L, is calculated to be 5378.01 m
Explanation:
Provided information:
Inner radius R1=2.5 cm
and outer radius R2= 5.8 cm.
The thickness of the spiral winding is (d) =1.6 \mu m = 1.6x 10^{-6} m
The total length of the spiral can be computed as
= 5378.01 m
