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jek_recluse
1 month ago
8

Now imagine you have several of such dipoles, and place them regularly between the plates. For this part of the pre-lab, you can

ignore any interactions between the dipoles themselves, and think of each dipole as interacting with the electric field of the plates only. What will be different now
Chemistry
1 answer:
castortr0y [3K]1 month ago
6 0
A dipole consists of a pair of equal but opposite charges. Since similar charges repel each other while opposite charges attract, when dipoles are placed in an electric field, the positive end is drawn toward the negative end of the field and vice versa. This behavior leads to movement or a stable position depending on how the field is aligned. If we consider the interaction with other dipoles, this influence might be hindered.
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Complete the passage: During the process of polymerization, combine by sharing electrons. This process forms a , which is made o
castortr0y [3046]
Monomers combine through electron sharing during the polymerization process. This leads to the formation of a polymer, which consists of repeating units. The resulting substance has various applications.
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1 month ago
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A 0.680 M Ca(OH)2 solution was prepared by dissolving 55.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
castortr0y [3046]
Convert 55.0g Ca(OH)2 to moles.

The calculation shows that 55.0g of Ca(OH)2 corresponds to 0.742 moles.

To find the volume, divide 0.742 mol of Ca(OH)2 by its molarity of 0.680M, yielding approximately 1.09L of Ca(OH)2.

If you disregard the negligible volume of the Ca(OH)2 itself, the resulting total volume of a 0.680M solution created by dissolving 55.0g of Ca(OH)2 in an appropriate amount of water would be 1.09L.
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2 months ago
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A sample of a compound that contains only the elements C, H, and N is completely burned in O2 to produce 44.0 g of CO2, 45.0 g o
alisha [2963]

Clarification:

To obtain the specific element, you should multiply the grams provided by the ratio of grams of that particular element within its complete compound.

Since the query did not indicate the amount of NO2 produced, we can consider its mass to be negligible, thus assigning 1 mole to Nitrogen.

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2 months ago
Given the initial rate data for the reaction A + B –––> C, determine the rate expression for the reaction.
Alekssandra [3086]

Answer:

B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]

Explanation:

For the reaction A + B → C

The expression for the reaction's rate is:

Δ[C]/Δt = k [A] [B]

Utilizing the values for [A], [B], and Δ[C]/Δt, multiply [A] by [B] to acquire a value of X and consider Δ[C]/Δt as Y. The slope derived from this linear regression will yield k.

Therefore, the results you should have are:

y = 3.60x10⁻² X

Thus, the reaction's rate is:

B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]

I hope this assists you!

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2 months ago
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