Answer:
Please refer to the explanation below.
Explanation:
There are numerous claims and methods to compare both solutions, the most common being concentration (or molarity) and %m/V.
Though both comparisons are valid, molarity is preferable since it provides a single figure indicating which solution is more concentrated.
To calculate the molarity of any solution, we use this formula:
M = n/V
n: the number of moles of solute.
V: the volume of the solution in liters.
As the solvent is water and the solute is a solid, the volume of the solution equals the solvent’s volume.
The common type of sugar, sucrose, has the molecular formula C12H22O11, with a molar mass of 342.3 g/mol.
This allows us to calculate the moles:
n = m/MM
n₁ = 5/342.3 = 0.0146 moles
n₂ = 10/342.3 = 0.0292 moles
Now, let’s determine the concentration of each solution:
M₁ = 0.0146 / 1 = 0.0146 M
M₂ = 0.0292 / 1 = 0.0293 M
Thus, we conclude that the second solution is more concentrated than the first. In other terms, M₂ > M₁
