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Angelina_Jolie
1 month ago
11

The standard free energy ( Δ G ∘ ′ ) (ΔG∘′) of the creatine kinase reaction is − 12.6 kJ ⋅ mol − 1 . −12.6 kJ⋅mol−1. The Δ G ΔG

value of an in vitro creatine kinase reaction is − 0.1 kJ ⋅ mol − 1 . −0.1 kJ⋅mol−1. At the start of the reaction, the concentration of ATP is 5 mM, 5 mM, the concentration of creatine is 17 mM, 17 mM, and the concentration of creatine phosphate is 25 mM. 25 mM. Using the values given, calculate the starting concentration of ADP in micromolar.
Chemistry
1 answer:
Tems11 [2.7K]1 month ago
3 0
The concentration of [ADP] is calculated to be 21.896*10^-6 μM. Using the data provided: creatine + ATP → ADP + creatine phosphate, with ΔG∘ = -12.6 KJ/mole and ΔG = -0.1 KJ/mole. Additional values include [Creatine phosphate] = 25 mM, [Creatine] = 17 mM, and [ATP] = 5mM. To find the concentration of [ADP], the following equation is used: ΔG = ΔG∘ + RTlnQc. By substituting the known values and rearranging, we find that Qc = 6.44*10^-3, leading to the concentration of [ADP] as 21.896*10^-6 μM.
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What is the kinetic energy acquired by the electron in hydrogen atom, if it absorbs a light radiation of energy 1.08x101 J. (A)
eduard [2782]

Explanation:

The following data has been provided:

Energy of radiation absorbed by the electron in the hydrogen atom = 1.08 \times 10^{-17} J

As energy is absorbed in the form of a photon, the frequency is calculated accordingly:

E = h \nu

1.08 \times 10^{-17} J = 6.626 \times 10^{-34} Js \times \nu

\nu = 0.163 \times 10^{17} s^{-1}

or, \nu = 1.63 \times 10^{16} s^{-1}

It is known that \nu = \frac{c}{\lambda}

1.63 \times 10^{16} s^{-1} = \frac{3 \times 10^{8} m/s}{\lambda}

\lambda = 1.84 \times 10^{-8} m

According to the De-Broglie equation \lambda = \frac{h}{p}

with p = m \times \nu

So, \lambda = \frac{h}{m \times \nu}

m \times \nu = \frac{6.626 \times 10^{-34} Js}{1.84 \times 10^{-8} m} = 3.6 \times 10^{-26} J/m

Squaring both sides gives us:

(m \times \nu)^{2} = (3.6 \times 10^{-26} J/m)^{2}

12.96 \times 10^{-52} = m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}

where m = mass of the electron

Therefore, m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}

=\frac{12.96 \times 10^{-52}}{9.1 \times 10^{-31}}

=1.42 \times 10^{-21} J

Since K.E = \frac{1}{2}m \nu^{2}

= \frac{1.42 \times 10^{-21} J}{2}

=0.71 \times 10^{-21} J

Our conclusion is that the kinetic energy gained by the electron in the hydrogen atom is 7.1 \times 10^{-22} J.

4 0
1 month ago
Which of the following air pollutants is correctly paired with one of its major effects?
alisha [2963]

Response:

The accurate choice is;

Sulfur oxides linked to acid precipitation

Details:

Sulfur oxide in the atmosphere interacts with oxygen, water, and other chemicals leading to the creation of acidic precipitation known as acid rain.

Sulfur oxides react with moisture in clouds to generate sulfuric acid as follows;

The sulfur gas undergoes initial oxidation

SO₂ + OH → HOSO₂

The subsequent step involves producing sulfur trioxide

HOSO₂ + O₂ → HO₂ + SO₃

Finally, sulfur trioxide reacts with water to yield sulfuric acid

SO₃ + H₂O → H₂SO₄ (aq).


3 0
1 month ago
The density of an alcohol is 0.788 g/mL. What volume in microliters, μL, will correspond to a mass of 20.500 mg?
lions [2927]

Answer:

B.  26.0 μL.

Explanation:

Hello,

Considering the provided mass and density, the volume calculates to be:

V=\frac{m}{\rho} =\frac{25.000mg}{0.788g/mL}*\frac{1g}{1000mg}*\frac{1000\mu L}{1mL} \\ \\V=26.0\mu L

Thus, the solution is B.  26.0 μL.

Best regards.

6 0
1 month ago
A given sample of caffeine, C8H10N4O2, has 6.47 x 1022
lorasvet [2795]
8.08 × atoms of hydrogen.
3 0
1 month ago
How to calculate electronegativity with 3 elements?
VMariaS [2998]
For instance, what is the difference in electronegativity for Acetone(CH2O)? Are there two distinct values, namely 0.4 for C versus H and 1.0 for C versus O? How do you decide which one to adopt?

6 Comments

AlwaysReady1

•

Apr 3, 2016, 10:14 PM

I may not fully grasp the question, but if you’re seeking to determine a compound's electronegativity to assess its electron-attracting capability, there are various other influencing factors.

It varies depending on the compound. For example, CH2O, known as formaldehyde, has oxygen with two pairs of electrons that can be donated. Neither hydrogen nor carbon can bond further as they are already fulfilling their valence shell requirements.

Robo94

•



You're attempting to apply a concept from a binary system to a more complex one. I assume you're aiming to figure out a molecule's dipole moment. In the case of a diatomic molecule (where A is bonded to B), the potential difference can simply be determined as A minus B. For larger molecules, the calculations become much more involved.

If this inquiry is related to homework assistance, it’s a distinctly different method from what you might be accustomed to. I recommend starting with water and then expanding out from there.

Check this out: https://www.khanacademy.org/science/organic-chemistry/gen-chem-review/electronegativity-polarity/v/dipole-moment

Philosoaxolotl

•



Electronegativity pertains to single elements (or rather individual atoms) and lacks straightforward applicability to broader molecules.

What precisely are you aiming to do with this data? If you're delving into how electrons transition between molecules, the situation is more intricate—within a molecule, the more electronegative elements pull electrons from other atoms (which frequently happens in organic compounds, such as when oxygen bonds with carbon and pulls in some of its electrons). Nevertheless, this effect diminishes in lengthened molecules. The system is more complicated as molecules do not possess a single, constant electronegativity (which is more accurate for atoms); instead, they exhibit varied localized charge regions that will respond differently.

From what I gather, your question pertains to the electronegativity difference among the atoms within an acetone molecule. This indeed relies on which two atoms you are examining and won't remain constant throughout; however, the difference won't simply match the values listed in an electronegativity table due to the factors discussed earlier.

This explanation might seem a bit hazy, and I’m just an undergraduate, so please take my interpretation lightly, but I am open to clarifying further if needed.

cheeseborito

•



That statement is inaccurate.

Electronegativity represents the attraction an atom holds for the electrons in a covalent bond with another atom. Essentially, an element does not have a singular electronegativity; it fluctuates based on its bonding partners. We cannot discuss the electronegativity of an atom in isolation.

While average values are useful for practical discussions (though they may not capture the nuance), the effective electronegativity of an oxygen atom bonded to carbon will remain fairly consistent.

As far as my understanding goes, even though my definition of electronegativity may lack precision, the influence an oxygen atom has on the electrons of a carbon atom is affected by what the carbon is bonded to. For instance, the local charge around the oxygen in acetic acid will be more pronounced than that in decanoic acid.

I may have phrased the electronegativity issue poorly—what I meant was the interaction between pairs of atoms as related to one another. An oxygen will exert a consistent pull regarding a carbon atom, but the changes in local charge can differ due to the influence of surrounding atoms, making the topics we typically utilize electronegativity to clarify substantially more intricate.
6 0
2 months ago
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