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Juli2301
20 days ago
8

A given sample of caffeine, C8H10N4O2, has 6.47 x 1022

Chemistry
1 answer:
lorasvet [2.5K]20 days ago
3 0
8.08 × atoms of hydrogen.
You might be interested in
A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W
eduard [2509]

Answer:

The salt identified is barium chloride.

Explanation:

BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX

The moles of barium sulfate produced are \frac{11.21 g}{233.38 g/mol}=0.0480 mol

per the reaction, 1 mole of barium sulfate arises from 1 mole of BaX_2.

Therefore, 0.0480 moles result from:

\frac{1}{1}\times 0.0480 mol=0.0480 mol of BaX_2.

The quantity of BaX_2 used amounts to 10.00 g

Moles of BaX_2 = \frac{10.00 g}{\text{Molar mass}}[/tex]

0.0480 mol=\frac{10.00}{\text{Molar mass}}

The molar mass of BaX_2 is 208.33 g/mol

The closest answer to our calculation is BaCl_2=208.2 g/mol.

The correct identification is barium chloride, which has a molar mass of 208.2 g/mol.

8 0
11 days ago
The ionic radius of a sodium ion is 2.27 angstroms (A) . What is this length in um
lions [2633]

\boxed{\sf 1Å=10^{-10}m}

\\ \rm\longmapsto 2.27Å

\\ \rm\longmapsto 2.27\times 10^{-10}m

\\ \rm\longmapsto 0.227\times 10^{-9}m

\\ \rm\longmapsto 0.0227\times 10^{-8}m

\\ \rm\longmapsto 0.00227\times 10^{-7}m

\\ \rm\longmapsto 0.00023\times 10^{-6}m

\\ \rm\longmapsto 0.00023\mu m

6 0
1 month ago
Why does 5060 have three significant figures?
Anarel [2593]

5060 has three significant figures: Below is the clarification

Explanation:

Significant figures

Significant figures (also referred to as significant digits and decimal places) in a number are those digits that carry substantial meaning.

These include all digits except: leading zeros.

Guidelines for determining significant figures

1. All non-zero digits are counted as significant. For instance, the number 23 has two significant figures.

2. Zeros located between two non-zero digits are significant; for example, 202.1201 contains seven significant figures.

3. Zeros preceding the significant figures are not significant. For example,.000021 has two significant figures, with zeros being non-contributory.

4. Zeros following the significant figures are significant.

This explains why the number 5060 has three significant figures.

3 0
28 days ago
En un balneario necesitan calentarse 1 millón de litros de agua anuales, subiendo la temperatura desde 15 ºC a 50 ºC y para ello
KiRa [2678]

Answer:

a) m_{CH_4}=2630kg

b) 1657 €

Explanation:

Hola,

a) En esta cuestión analizaremos el millón de litros de agua anualmente, dado que este dato nos permite calcular el calor necesario para calentar dicha cantidad, considerando que la densidad del agua es de 1 kg/L:

Q_{H_2O}=m_{H_2O}Cp(T_2-T_1)=1x10^6LH_2O*\frac{1kgH_2O}{1LH_2O}*4.18\frac{kJ}{kg\°C}(50-15) \°C\\Q_{H_2O}=146.3x10^6kJ

A continuación, utilizamos la entalpía de combustión del metano para determinar la cantidad en kilogramos necesaria, ya que la energía calórica perdida por el metano es equivalente a la energía obtenida por el agua:

Q_{H_2O}=-Q_{CH_4}=-146.3x10^5kJ=m_{CH_4}\Delta _cH_{CH_4}

m_{CH_4}= \frac{Q_{CH_4}}{\Delta _cH_{CH_4}} =\frac{-146.3x10^5kJ}{-890kJ/molCH_4} *\frac{16gCH_4}{1molCH_4} \\\\m_{CH_4}=2630112.36g=2630kg

b) En este supuesto, tenemos que, bajo condiciones normales de 1 bar y 273 K, el precio de 1 metro cúbico de metano es 0,45 €, lo que nos permite calcular las moles de metano en esas condiciones:

n_{CH_4}=\frac{PV}{RT}=\frac{1atm*1000L}{0.082\frac{atm*L}{mol*K}*273K} =44.67mol

En consecuencia, los kilogramos de metano que se obtienen por 0,45 € son:

44.67molCH_4*\frac{16gCH_4}{1molCH_4}*\frac{1kg}{1000g} =0.715kgCH_4

Finalmente, usando regla de tres:

0.715 kg ⇒ 0.45 €

2630 kg ⇒ X

X = (2630 kg x 0.45 €) / 0.715 kg

X = 1657 €

Regards.

3 0
29 days ago
In the compound k[co(c2o4)2(h2o)2] (where c2o42– = oxalate) the oxidation number and coordination number of cobalt are, respecti
castortr0y [2720]
Let's represent molecules with symbols as follows:

                   C₂O₄  =  X
and
                    H₂O  =  Y
Then,
                                K [ Co (X)₂ (Y)₂ ]

Since Potassium (K) has an oxidation number of +1

To achieve neutrality, the oxidation number of the coordination sphere needs to equal -1.
Thus,
                                    [ Co (X)₂ (Y)₂ ]  =  -1
Given that,
           the O.N of X is -2
Therefore,
       O.N of (X)₂ equals -4

Additionally,
O.N of H₂O is zero since it remains neutral. Therefore,

                                    [Co - 4 + 0 ]  =  -1
Or,
                                    Co  =  -1 + 4

                                    Co  =  +3

Conclusion:
          The oxidation number for the coordination sphere is -1, and the oxidation state of copper is +3.
6 0
27 days ago
Read 2 more answers
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