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jekas
11 days ago
9

A plasma is a gas of ionized (charged) particles. When plasma is in motion, magnetic effects "squeeze" its volume, inducing inwa

rd pressure known as a pinch. Consider a cylindrical tube of plasma with radius R and length L moving with velocity v along its axis. If there are n ions per unit volume and each ion has charge q , we can determine the pressure felt by the walls of the cylinder.
Required:
a. What is the volume charge density p in terms of n and q?
b. The thickness of the cylinder surface is n^1/3. What is the surface charge density σ in terms of n and q?
Physics
1 answer:
Softa [2.9K]11 days ago
5 0

Answer:

 a

    The density of volume charge is  \rho = nq

b

    The density of surface charge is  \sigma = n^{\frac{2}{3} } q

Explanation:

The question states that

    The radius measures  R

     The length is L

       The speed is  v

        The ion count per unit volume is  n

         The charge per ion is  q

          The surface thickness of the cylinder is  n^{\frac{1}{3} }

The volume charge density is mathematically expressed as

      \rho = nq

The surface charge density is mathematically expressed as

    \sigma = \rho n^{\frac{1}{3} }

substituting for  \rho

     \sigma = n * n^{\frac{1}{3} } q

     \sigma = n^{\frac{2}{3} } q

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If an electronic circuit experiences a loss of 3 decibels with an input power of 6 watts, what would its output power be, to the
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Answer:

The output power of the circuit is 3 Watts.

Given:

a loss in decibels = 3 dB

Input power = 6 Watts

To find:

What is the output power?

Formula used:

Output power = Input power × loss in ratio

Solution:

3 dB loss corresponds to a ratio of 0.5

Output power can be calculated as follows:

Output power = Input power × loss in ratio

Output power = 6 × 0.5

Output power = 3 Watts

Therefore, the output power of the circuit is 3 Watts.

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The vehicle experiences a normal force of 4440 N. The normal force acts perpendicular to the ground surface. Key details include the vehicle's mass of 1200 kg and the gravitational force of 3.7 N/kg. We calculate the normal force in Newtons by multiplying these two figures: force = field strength * mass = 3.7 N/kg * 1200 kg = 4440 N.
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A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0. Wha
serg [3462]

Answer:

a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

Explanation:

Data provided

initial velocity v₀=20 cm/s at time t=3s

final velocity vf=0 at time t=8 s

Required

Average Acceleration for the interval from 3s to 8s

Solution

Acceleration can be defined as the first derivative of velocity concerning time

a_{acceleriation} =\frac{dv_{velocity}}{dt_{time}}\\a_{acceleriation} =\frac{v_{f}-v_{o} }{dt}\\ a_{acceleriation} =\frac{0-20cm/s }{8s-3s}\\ a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

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In a third class lever, the distance from the effort to the fulcrum is ____________ the distance from the load/resistance to the
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The full sentence states:
In a third class lever, the distance between the effort and the fulcrum is LESS than the distance between the load/resistance and the fulcrum.
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16 days ago
A large box of mass m sits on a horizontal floor. You attach a lightweight rope to this box, hold the rope at an angle θ above t
inna [2982]

Answer:

The answer to the specified question will be "\mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}".

Explanation:

Referring to the question,

\sum F_{x}

⇒  TCos \theta-F_{s}=0

⇒  T_{m}Cos \theta =F_{s}...(equation 1)

\sum F_{y}

⇒  TSin \theta+F_{N}=m_{g}

⇒  M_{g}-TSin \theta=F_{N}...(equation 2)

Now,

From equation 1 and equation 2, we conclude

⇒  T_{m} Cos \theta = \mu_{s}F_{N}

By substituting the value of F_{N}, we derive

⇒  T_{m} Cos\theta = \mu_{s}(M_{g}-T_{m}Sin \theta)

⇒  \mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}

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1 month ago
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