The formula for the kinetic energy of any object in motion is
(1/2) (mass) (velocity²).
For the object you've mentioned, it translates to
(1/2) (100 kg) (12.5 m/s)²
= (50 kg) (156.25 m²/s²)
= 7,812.5 joules
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Beware that your attachment is heavily blurred and unreadable.
Explanation:
- A substance will float if it has a lower density than the liquid it is placed in.
- A substance will sink if its density exceeds that of the liquid.
Density of corn syrup = 
1) Density of gasoline = 
Gasoline's density is less than that of corn syrup, indicating it will float in corn syrup.
2) Density of water = 
Water's density is also less than that of corn syrup, meaning it will float in corn syrup.
3) Density of honey = 
Honey's density exceeds that of corn syrup, so it will sink in corn syrup.
4) Density of titanium = 
The density of titanium is greater than that of corn syrup, hence it will sink in corn syrup.
In this scenario, there exists a constant electric field produced by a large sheet. This electric field can be defined as... The force acting on the ball due to this field acts horizontally, and this force must be counterbalanced by the horizontal tension component of the string to maintain equilibrium. Similarly, the vertical tension component in the string must equal the weight of the small sphere. Hence, we can derive two equations to illustrate this.
The rise in fluid level is 0.11 m, and for mercury, it is 0.728 cm or 7.28 mm. \nTo solve this, here’s the information we have: \n- Density of oil: [density value] \n- Change in pressure in the tank: [pressure change] \n- Density of mercury: [density value] \nTo find the fluid level rise in the manometer: \n1 mmHg equals 133.332 Pa. \nBased on the variables: g is the acceleration due to gravity and h represents the height of the fluid level. \nh = 0.11 m. \nUsing mercury, we find: \nh = 0.00728 m, which is 7.28 mm.
The energy contained in a photon is determined by the formula:

where h represents the Planck constant and f signifies the frequency of the photon. Given the energy of the photon,

, we can rearrange the equation to deduce the photon's frequency:

Now, we can use the relationship that links frequency f, wavelength

, and the speed of light c to ascertain the wavelength of the photon: