Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade

Answer:

(C) They have the same coefficient of variation

Step-by-step explanation:

The coefficient of variation (CV) is calculated using the formula:

Where represents standard deviation and represents the mean.

Bob's average weight is 200 pounds with a standard deviation of 16 pounds

This indicates that .

Thus, his coefficient of variation is

Mary's average weight is 125 pounds, with a standard deviation of 10 pounds.

This implies

Therefore, her coefficient of variation is

Since both have the same coefficient of variation, the accurate response is.

(C) They have the same coefficient of variation

The answer is $300,000. Detailed calculation: Labor cost = $11,000; Parking cost = $7,000; Therefore, Parking Labor cost = $18,000. The parking labor cost represents 6% of the parking revenue. Thus, 6% = Parking Labor cost / Parking Revenue. By substituting, we get 6/100 = $18,000 / Parking Revenue. Solving for Parking Revenue yields: Parking Revenue = (100 × $18,000) / 6 = $300,000.

Response:

$144,843.5

Detailed explanation:

In this scenario, we will utilize the compound interest formula

A= P(1+r)^t

A = final amount

P = initial principal

r = interest rate

t = number of periods

Given parameters

P= $27,000

R= 7.25%= 7.25/100= 0.0725

T= 24

A=27000(1+0.0725)^24

A= 27000(1.0725)^24

A= 27000*5.364

A= $144,843.5

By the end of 24 years, her account balance will reach $144,843.5

Hello! C and D aren't correct answers, as they fall downward due to gravity. The object accelerates downward at -10 m/s, resulting in an increasing speed as it descends, going beyond 10 m/s, which indicates that speed isn't steady. Hence, the correct answer is A.

Answer:

Translate the circles so they align at a common center and subsequently enlarge circle Y using a scale factor of 3 ⇒ 3rd answer

Step-by-step explanation:

* Let's describe how to approach this problem

- To establish that all circles are similar, a translation and a dilation factor are necessary to align one circle with another

- We can reposition the circles to coincide at the center and then expand one of the circles by the defined scale factor, with the center of dilation being the common point for all circles.

* Let's resolve the issue

∵ Circle X displays a radius of 6 units

∵ Circle Y has a radius of 2 units

- Initially, we shift the circles so they coalesce at a central point

∴ We utilize translation to place the centers of both circles at the same location

- Determine the dilation factor based on the different radii of the circles

∵ The radius of circle X measures 6 units

∵ The radius of circle Y measures 2 units

∴ Therefore, the scale factor is calculated as 6/2 = 3

∴ Enlarge circle Y by a scale factor of 3

* The actions that affirm the circles are similar are as follows;

  Translate the circles so they share a common center point, and

  enlarge circle Y by a factor of 3.