After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38

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After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38

m/s on flat ground. Assuming that his car travels with a constant acceleration, calculate the maximum speed (Vm), in meters per second, his car can reach on flat ground?\

Physics

1 answer:

Sav [3.1K] · Answer 1 · 2026-03-30T10:25:50+03:00

Answer:

64.2 m/s

Explanation:

Given that

Speed,v=38 m/s

We need to calculate the maximum speed when his car reaches flat ground.

By using dimensional analysis

$F_{res}\propto v^2$

If a reduction of 35% in acceleration due to F(res) occurs at 38 m/s

Then, a complete 100% reduction in acceleration can be achieved by F(res) at v' m/s

$\frac{F_1}{F_2}=\frac{v^2}{v'^2}$

$v'^2=\frac{F_2}{F_1}v^2$

$v'=v\sqrt{\frac{F_2}{F_1}}$

By substituting the values

$v'=38\times \sqrt{\frac{100}{35}}$

$v'=64.2 m/s$

Thus, the maximum speed achievable when his car is on flat ground is 64.2 m/s