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7 days ago

A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an

additional 5.0 cm and released. Its position as a function of time is approximately what? Group of answer choices

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While looking at bromine (Br) on the periodic table, a student needs to find another element with very similar chemical properti

Sav [3153]

Response: Numerous elements can be found, all situated within the same vertical column as bromine.

Explanation:

Elements are organized by their atomic numbers on the periodic table. Those in the same vertical column (known as groups) exhibit the same valence electron configurations, resulting in similar chemical characteristics. Consequently, there are numerous elements sharing analogous chemical properties grouped with Bromine.

7 0

3 months ago

Read 2 more answers

Consider the uniform electric field \vec{E} =(4000~\hat{j}+3000~\hat{k})~\text{N/C} E ⃗ =(4000 j ^ +3000 k ^ ) N/

kicyunya [3294]

Answer:

Electric flux is calculated as $\phi=31562.63\ Nm^2/C$

Explanation:

We start with the given parameters:

The electric field impacting the circular surface is $E=(4000j+3000k)\ N/C$

Our objective is to ascertain the electric flux passing through a circular region with a radius of 1.83 m situated in the xy-plane. The area vector is oriented in the z direction. The formula for electric flux is expressed as:

$\phi=E{\cdot}A$

$\phi=(4000j+3000k){\cdot}Ak$

Applying properties of the dot product, we calculate the electric flux as:

$\phi=3000\times Ak$

$\phi=3000\times \pi (1.83)^2$

$\phi=31562.63\ Nm^2/C$

Consequently, the electric flux for the circular area is $\phi=31562.63\ Nm^2/C$ . Thus, this represents the required answer.

4 0

2 months ago

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant

Yuliya22 [3333]

Answer:

$v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s$

Explanation:

In this scenario, we determine the initial velocity as follows:

$v_i = 7 \frac{m}{s}$

The final velocity in this instance can be expressed as:

$v_f = 13 \frac{m}{s}$

It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:

$v_f = v_i +at$

Solved for acceleration, we find:

$a = \frac{v_f -v_i}{t} = \frac{13 m/s -7 m/s}{8 s}= 0.75 \frac{m}{s^2}$

For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:

$v_f = v_ i +a t$

Substituting into the equation yields:

$v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s$

5 0

3 months ago

A communications satellite orbiting the earth has solar panels that completely absorb all sunlight incident upon them. The total

Ostrovityanka [3204]

Answer:

0.000047N

Explanation:

We know that

intensity (I) = P/ A

Where

P= power

A= Area

Thus, the power absorbed can be calculated as:

Power = Intensity x Area

This equals = 1.4 x 10^3 x(10)

Thus,

14000 Watts = 14 kWatt

However, the radiation pressure can be defined as

time-averaged intensity divided by the speed of light in a vacuum

So,

P = (1.4 x 1000)/c

Also,

F= P x A

Thus,

((1.4 x 1000)/(3 x10^8)) x 10

This results in

=0.000046666N

Rounded to two significant figures gives us

=0.000047 N

3 0

2 months ago