<span>A force of 110 N is applied at an angle of 30</span>°<span> to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.
For the component parallel to the ground:
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26
For the component perpendicular to the ground:
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
Answer:
Speeds of 1.83 m/s and 6.83 m/s
Explanation:
Based on the law of conservation of momentum,
where m represents mass, 
is the initial speed before impact, 
and 
are the velocities of the impacted object after the collision and of the originally stationary object after the impact.
Thus, 
After the collision, the kinetic energy doubles, therefore:
Substituting the initial velocity of 5 m/s provides the equation needed to proceed.
We know that leads to 
Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25. 
By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.
Answer:
Explanation:
Let the charge on the large droplet be denoted as Q.
When the radius of the droplet is R, the electric potential for the larger droplet can be expressed as:
If it splits into n identical droplets, let the charge of each be "q" and their radius be "r".
Applying volume conservation gives us:
Now, the potential for the smaller droplets is given as:
Answer:
The book is titled Solid State or Condensed Matter
Explanation:
Answer:
Explicación:
Definamos v como la velocidad lineal, ω como la velocidad angular e I como el momento de inercia del disco.
La energía cinética (lineal) = 1/2 mv²
La energía cinética rotacional = 1/2 I ω²
I = 1/2 m r² (donde m y r son la masa y el radio del disco)
La energía cinética rotacional = 1/2 x1/2 m r² ω²
= 1/4 m v² (v = r ω)
Energía total
= Energía cinética (lineal) + Energía cinética rotacional
= 1/2 mv² + 1/4 mv²
= 3/4 mv²
La relación de K E rotacional / K E total = 1/4 m v² / 3/4 mv²
= 1 /3
Por lo tanto, 1 /3 de la energía total se debe a la energía cinética rotacional.
