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Alenkasestr
3 months ago
6

In a computer-based experiment to study diffraction, the width of the central diffraction peak is 15.20 mm. The wavelength of th

e laser is 638 ????m (1 ????m = 10-. m) and the distance from the screen containing the slits to the camera screen is 68.0 cm. Calculate the slit width ( make sure all your values are meters).Which equation should I use? slit width = (2)(638*10^-9)(0.68)/(15.20*10^-3) OR slit width = (1)(638*10^-9)(0.68)/(15.20*10^-3)? please explain why.
Physics
1 answer:
serg [3.5K]3 months ago
3 0
In this diffraction experiment, the width of the central maximum peak equals 15.20 mm, and the laser wavelength is 638 nm. The distance from the camera screen to the slits measures 68.0 cm. To find the slit width, one must use the appropriate equation, considering this parameter when values are expressed in meters.
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A simple watermelon launcher is designed as a spring with a light platform for the watermelon. When an 8.00 kg watermelon is put
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To tackle this problem, it's essential to employ concepts associated with force as per Hooke's law, alongside the forces described by Newton's second law and the concept of potential elastic energy. Since the forces are in equilibrium, the spring force matches the gravitational force. To find the spring constant k, we recognize the compression is 40cm at launch, hence applying the potential elastic energy formula results in determining the energy stored in the spring as 63.72 Joules.
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3 months ago
A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by
kicyunya [3294]

Answer:

W = -510.98 J

Explanation:

Force = 43 N, 61° SW

Displacement = 12 m, 22° NE

The work done is calculated using:

W = F*d*cos(A)

where A is the angle between the applied force and displacement.

The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°

Hence, W = 43 * 12 * cos(172)

This results in W = -510.98 J

The negative result indicates that the work is done contrary to the direction of the force applied.

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3 months ago
A block moves at 5 m/s in the positive x direction and hits an identical block, initially at rest. A small amount of gunpowder h
Yuliya22 [3333]

Answer:

Speeds of 1.83 m/s and 6.83 m/s

Explanation:

Based on the law of conservation of momentum,

mv_o=m(v_1 + v_2)where m represents mass, v_o is the initial speed before impact, v_1 and v_2 are the velocities of the impacted object after the collision and of the originally stationary object after the impact.

5m=m(v_1 +v_2)

Thus, v_1+v_2=5

After the collision, the kinetic energy doubles, therefore:

2m*(0.5mv_o)=0.5m(v_1^{2}+v_2^{2})

2v_o^{2}=v_1^{2} + v_2^{2}

Substituting the initial velocity of 5 m/s provides the equation needed to proceed.v_o

2*(5^{2})= v_1^{2} + v_2^{2}We know that v_1+v_2=5 leads to v_1=5-v_2

50=(5-v_2)^{2}+ v_2^{2}

50=25+v_2^{2}-10v_2+v_2^{2}

2v_2^{2}-10v_2-25=0

Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25. v_2=6.83 m/s

By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.

6 0
3 months ago
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