In a computer-based experiment to study diffraction, the width of the central diffraction peak is 15.20 mm. The wavelength of th

Question

1 month ago

6

In a computer-based experiment to study diffraction, the width of the central diffraction peak is 15.20 mm. The wavelength of th

e laser is 638 ????m (1 ????m = 10-. m) and the distance from the screen containing the slits to the camera screen is 68.0 cm. Calculate the slit width ( make sure all your values are meters).Which equation should I use? slit width = (2)(638*10^-9)(0.68)/(15.20*10^-3) OR slit width = (1)(638*10^-9)(0.68)/(15.20*10^-3)? please explain why.

Physics

1 answer:

serg [3.5K] · Answer 1 · 2026-03-15T23:18:19+03:00

In this diffraction experiment, the width of the central maximum peak equals 15.20 mm, and the laser wavelength is 638 nm. The distance from the camera screen to the slits measures 68.0 cm. To find the slit width, one must use the appropriate equation, considering this parameter when values are expressed in meters.