To tackle this problem, it's essential to employ concepts associated with force as per Hooke's law, alongside the forces described by Newton's second law and the concept of potential elastic energy. Since the forces are in equilibrium, the spring force matches the gravitational force. To find the spring constant k, we recognize the compression is 40cm at launch, hence applying the potential elastic energy formula results in determining the energy stored in the spring as 63.72 Joules.
Answer:
W = -510.98 J
Explanation:
Force = 43 N, 61° SW
Displacement = 12 m, 22° NE
The work done is calculated using:
W = F*d*cos(A)
where A is the angle between the applied force and displacement.
The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°
Hence, W = 43 * 12 * cos(172)
This results in W = -510.98 J
The negative result indicates that the work is done contrary to the direction of the force applied.
Answer:
Speeds of 1.83 m/s and 6.83 m/s
Explanation:
Based on the law of conservation of momentum,
where m represents mass,
is the initial speed before impact,
and
are the velocities of the impacted object after the collision and of the originally stationary object after the impact.
Thus,
After the collision, the kinetic energy doubles, therefore:
Substituting the initial velocity of 5 m/s provides the equation needed to proceed.
We know that
leads to
Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25.
By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.