Let X denote <span>the baby’s weight.
Let y represent </span>the doctor’s weight.
Let z stand for the nurse’s weight.
From the equations: x + y = 78 implies y = 78 - x
and x + z = 69 gives z = 69 - x
then we have x + y + z = 142
Substituting y = 78 - x and z = 69 - x into the equation x + y + z = 142
x + y + z = 142
x + 78 - x + 69 - x = 142
-x + 147 = 142
-x = -5
x = 5
Conclusion
<span>the baby’s weight was 5 kg</span>
An ANOVA test is the appropriate method. Step-by-step explanation: The ANOVA test, which assesses the means of more than two samples, will be applied here. Given that three different test groups were utilized, this statistical test will be necessary for determining if the means are the same. Note that this test merely informs us of the means' equality, not which mean surpasses the others; for that determination, three separate hypothesis tests would be required, comparing two means at a time.
Which equivalent fraction corresponds to
? -
since
-
as
and
- 
because and
- 
since 
The answer is
- because and
A fraction is deemed equivalent if it maintains the same value when expressed in simplest terms. The equivalent to is found in the chosen option;
First, halve both the numerator and denominator by 2
Then reduce further
2/2 = 1 and 6/2 = 3; Thus;
Next, multiply both the numerator and denominator by 3
Therefore, equals .
Answer:
(a) 4i iterations
(b) "i × n" iterations
Step-by-step explanation:
(a) The provided algorithm segment shows:
for i:= 1 to 4, (Outer loop)
for j:= 1 to i (Inner loop)
next j,
next i
The inner loop executes i times while the outer loop completes 4 cycles.
The inner loop’s total execution when the full algorithm runs is:
= i × 4
= 4i iterations
(b) In the given algorithm segment;
for i:= 1 to n, (Outer loop)
for j:= 1 to i (Inner loop)
next j,
next i
where n denotes a set of positive integers.
<pthe inner="" loop="" also="" runs="" for="" times="" and="" the="" outer="" times.=""><pthus the="" total="" iterations="" of="" inner="" loop="" for="" entire="" algorithm="" is:="">
= i × n
= "i × n" iterations
</pthus></pthe>
you can set this up with the equation;
x + (x + 42) = 138
start by combining like terms;
2x = 138 - 42
2x = 96
x = 96/2
x = 48
we've found x now plug it back into the original equation.
48 + (48 + 42) = 138
48 + 90 = 138
hope it helped...if you have any concerns just let me know:)
