Answer: See explanation
Step-by-step explanation:
To determine how many boxes of sugar Alonso can purchase, we can express the scenario as follows:
= 2.75 + 11.50S ≤ 55
Expanding this gives us:
2.75 + 11.50S ≤ 55
11.50S ≤ 55 - 2.75
11.50S ≤ 52.25
S ≤ 52.25 / 11.50
S ≤ 4.54
Thus, he is able to buy 4 boxes of sugar.
8 out of 300 were defective.
That corresponds to 80 pairs being defective
Response:
first option
Detailed explanation:
The equation expressing a proportional relationship is
y = kx ← with k as the proportional constant
Here k takes the value of 0.7, hence
y = 0.7x ← represents the required equation
Given
= 
(cross-multiply)
10y = 7x (dividing both sides by 10)
y = x = 0.7 x ← emerges as the needed equation
Answer:
Answer and Explanation:
We have:
Population mean,
μ
=
3
,
000
hours
Population standard deviation,
σ
=
696
hours
Sample size,
n
=
36
1) The standard deviation for the sampling distribution:
σ
¯
x
=
σ
√
n
=
696
√
36
=
116
2) By the central limit theorem, the sampling distribution's expected value matches the population mean.
Thus:
The expected value of the sampling distribution equals the population mean,
μ
¯
x
=
μ
=
3
,
000
The standard deviation of the sampling distribution,
σ
¯
x
=
116
The sampling distribution of
¯
x
is roughly normal due to a sample size greater than
30
.
3) The likelihood that the average lifespan of the sample falls between
2670.56
and
2809.76
hours:
P
(
2670.56
<
x
<
2809.76
)
=
P
(
2670.56
−
3000
116
<
z
<
2809.76
−
3000
116
)
=
P
(
−
2.84
<
z
<
−
1.64
)
=
P
(
z
<
−
1.64
)
−
P
(
z
<
−
2.84
)
=
0.0482
In Excel: =NORMSDIST(-1.64)-NORMSDIST(-2.84)
4) The probability of the average life in the sample exceeding
3219.24
hours:
P
(
x
>
3219.24
)
=
P
(
z
>
3219.24
−
3000
116
)
=
P
(
z
>
1.89
)
=
0.0294
In Excel: =NORMSDIST(-1.89)
5) The likelihood that the sample's average life is lower than
3180.96
hours:
P
(
x
<
3180.96
)
=
P
(
z
<
3180.96
−
3000
116
)
=
P
(
z
<
1.56
)
=
0.9406
