If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in

To respond to the previous question:
<span>Q = heat quantity (kJ) </span>
<span>cp = specific heat (kJ/kg.K) = 4.187 kJ/kgK </span>
<span>m = weight (kg) </span>
<span>dT = temperature change between hot and cold water (K). Note: dt in °C is identical to dt in Kelvin </span>

<span>Q = 100kg * (4.187 kJ/kgK) * 15 K </span>
<span>Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal</span>